Sigma Percentile
JEE Main 2024 (30 Jan Shift 1)
LEVELBoard

Animated Solution for Mathematics - Complex Numbers: If , satisfies the equation , then is equal to :

Select Answer:

Visualized Solution

The Given Equation

  • Given equation:
  • Condition: , where
  • Objective: Find

Rearranging the Equation

  • Isolate the terms to analyze magnitudes.

Taking Modulus on Both Sides

  • Apply modulus to both sides of the equation.

Properties of Modulus

  • Power rule:
  • Product rule:
  • Conjugate rule:

Simplifying the Equation

  • Left side:
  • Right side:
  • Result:

Solving for

  • Rearrange:
  • Factorize:
  • Possible roots: or

Applying the Constraint

  • Given constraint:
  • If , then and , which means .
  • This violates the constraint!

The Valid Solution

  • Therefore, the only valid magnitude is .
  • This means lies on the unit circle, but not on the axes.

Final Calculation

  • We need to find .
  • Since , squaring both sides gives:
  • Final Answer:

The Sigma Insight: Conjugate and Modulus

Solution Diagram

Analyzing the Setup

Welcome, fellow traveler on the path to JEE mastery. Today, we are not just solving an equation; we are exploring the beautiful, hidden symmetry of the complex plane.
We are given the equation , with the vital constraint that $xy eq 0$. This constraint is not just a footnote; it is a signpost telling us that our solution cannot lie on the axes. Let us embark on this journey to find .

The Strategic Rearrangement

When you face an equation like , your first instinct might be to expand into . While that is a valid path, it is often a path through a dense forest of algebra.
Instead, let us look for a more elegant route. We want to isolate the terms to analyze their magnitudes. By moving the term to the right side, we get:
This simple act of balancing the equation is the first step toward clarity. We have now separated the complex variables, setting the stage for a powerful transformation.

The Modulus Transformation

Now, we arrive at the most critical moment of our journey. Whenever you see an equation containing both and its conjugate , taking the modulus on both sides is a transformative tool.
It acts like a lens, focusing our attention on the distance from the origin rather than the specific coordinates. Applying the modulus, we get:
This step is profound because it converts a complex equation into a real-valued one, stripping away the imaginary components that often obscure the truth.

The Toolkit of Properties

To proceed, we must reach into our mathematical toolkit. We recall three fundamental properties of the modulus: the power rule , the product rule , and the conjugate rule .
These are not just formulas; they are the laws of the complex universe. Applying these, the left side of our equation, , becomes . On the right side, we split the modulus:
Since and , the right side simplifies beautifully to just . Our complex equation has now collapsed into the simple, elegant form:

The Trap and the Truth

We are almost there, but we must be careful. A common mistake is to simply divide by , which would lose a potential solution.
Instead, we bring everything to one side:
Factoring this, we get . This gives us two possibilities: or .
This is where the constraint $xy eq 0$ becomes our guide. If , then must be the origin, meaning and , which makes . This violates our constraint! Thus, we reject . The only valid solution is .

Final Calculation

We have arrived at the destination. We know .
The question asks for . Since , it follows that:
We have navigated the traps, applied the properties, and arrived at the answer with precision. The final result is 1.

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