Sigma Percentile
JEE Advanced 2023
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: Let be complex number satisfying , where denotes the complex conjugate of . Let the imaginary part of be nonzero. Match each entry in List-I to the correct entries in List-II.

List-I

(P)
(P) is equal to
(Q)
(Q) is equal to
(R)
(R) is equal to
(S)
(S) is equal to

List-II

(1)
(1) 12
(2)
(2) 4
(3)
(3) 8
(4)
(4) 10
(5)
(5) 7

Select Matching Pairs:

PMatches
QMatches
RMatches
SMatches

Visualized Solution

Analyzing the Equation

  • Given equation:
  • Condition:

The Conjugate Strategy

  • Take conjugate of both sides:
  • Properties: , ,

The Conjugated Equation

  • Original (1):
  • Conjugated (2):

Subtracting the Equations

  • Rearranging:

Factorizing the Difference

  • Factoring out :

Applying the Imaginary Condition

  • Since , is not purely real.
  • Therefore,

Finding the Real Part

  • Let
  • So, (where )

Substituting back to Original

  • Substitute into
  • Equation:

Expanding and Simplifying

  • Sum of these parts:
  • The equation becomes:

Solving for y

  • Divide by (since ):
  • Squaring both sides:

The Complex Number z

  • Note:

Evaluating (P)

  • (P)
  • So, (P) matches with (2).

Evaluating (Q)

  • (Q)
  • So, (Q) matches with (1).

Evaluating (S)

  • (S)
  • So, (S) matches with (5).

Final Match

  • (R) (Not in options)
  • Assuming intended expression was
  • Matches: , ,
  • Key Takeaway: Taking the conjugate of an equation is a powerful tool.

The Sigma Insight: Conjugate and Modulus

Solution Diagram

Analyzing the Setup

We are tasked with solving the equation under the constraint that $\text{Im}(z) eq 0$.
While substituting is a standard approach, it often leads to cumbersome algebraic expressions. Instead, we will utilize the symmetry of the complex plane to simplify the problem.

The Mirror Strategy

The presence of both and suggests we should examine the conjugate of the entire equation. Taking the conjugate of both sides, we obtain:
Since is a real number and the conjugate of a sum is the sum of conjugates, this simplifies to:

The Algebraic Cleansing

We now have two equations: 1) 2)
Subtracting the second equation from the first eliminates the and the constant term:
Using the difference of squares identity , we factor the expression:

Applying Constraints

Given the constraint $\text{Im}(z) eq 0$, we know that $z eq \bar{z}$, which implies $(z - \bar{z}) eq 0$.
We can safely divide by to arrive at the simplified condition:
Since , we conclude that the real part of is .

The Final Reveal

Substituting into the original equation , where :
Let . Then , and the equation becomes , which simplifies to . Since $u eq 0$, we have , so .
Thus, , which gives , or . The solutions are .

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