Sigma Percentile
JEE Advanced 2008
LEVELJEE Main

Animated Solution for Mathematics - Probability: An experiment has 10 equally likely outcomes. Let and be non-empty events of the experiment. If consists of 4 outcomes, the number of outcomes that must have so that and are independent, is

Select Answer:

Visualized Solution

Defining the Sample Space

  • Total number of outcomes:

Event and its Probability

  • Number of outcomes in Event :
  • Probability of Event :

Defining Event and Intersection

  • Let
  • Let

The Condition for Independence

  • For and to be independent:

Setting up the Equation

  • Substitute:

Simplifying the Relation

  • Multiply both sides by :

Applying Integer Constraints

  • must be an integer.
  • Therefore, must be divisible by .
  • Since , must be a multiple of .

Bounding the Values of

  • is a non-empty event:
  • Maximum outcomes in :
  • Constraints on :

Testing the First Multiple

  • Possible multiples of :
  • If :
  • (Valid integer)

Testing the Second Multiple

  • If :
  • (Valid integer)

The Final Answer

  • Conclusion:
  • The number of outcomes must have is or .

The Sigma Insight: Addition and Multiplication Theorems

Solution Diagram

Analyzing the Setup

Imagine you are standing before a vast, empty canvas representing our sample space, a set of ten equally likely outcomes. This is our universe, , where .
Within this universe, we have an event that claims four of these outcomes for itself. We know , which gives us a probability:
Now, we introduce a mysterious event . We do not know its size, so let us call it , meaning . We also have an intersection, the shared territory between and , which we will call , so .

The Heart of Independence

What does it truly mean for two events to be independent? It means that the occurrence of one provides absolutely no information about the occurrence of the other.
Mathematically, this is expressed as the elegant condition:
This is the heartbeat of our problem. Let us translate this into the language of our counts. We know , , and .
Substituting these into our independence condition, we get:

The Algebraic Journey

Now, let us simplify this. Multiplying both sides by 10, we find:
This is a beautiful, simple relationship. However, we must respect the constraints of our reality. Since is the number of outcomes in the intersection of two sets, it must be an integer.
For to be an integer, must be divisible by 5. Since 2 and 5 share no common factors, itself must be a multiple of 5.

The Final Revelation

We know that is a non-empty event, so . We also know that is a subset of our sample space of ten, so .
The multiples of 5 in the range are exactly 5 and 10. Let us test them:
If , then , which is a valid integer.
If , then , which is also a valid integer.
Thus, the possible values for the number of outcomes in are 5 and 10. We have navigated the constraints, respected the definitions, and arrived at the truth.

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