Sigma Percentile
JEE Main 2013
LEVELJEE Main

Animated Solution for Mathematics - Quadratic Equations: If the equations and , have a common root, then is

Select Answer:

Visualized Solution

Analyze

  • Given quadratic equation:
  • Let's visualize it as a function .

Discriminant Formula

  • To find the nature of roots, we use the Discriminant ().

Substitute Coefficients

  • Comparing with standard form:
  • , ,
  • Substitute into formula:

Calculate

Nature of Roots

  • Since , the roots are imaginary (complex).
  • Geometrically, the parabola never intersects the x-axis.

Conjugate Pair Theorem

  • Conjugate Pair Theorem:
  • If coefficients are real, complex roots occur in conjugate pairs.
  • If is a root, is also a root.

Second Equation

  • Given:
  • Coefficients .
  • It shares a common root with .

Both Roots Common

  • Since one root is complex, its conjugate must also be a root.
  • Therefore, both roots must be common.
  • The equations are identical, just scaled.

Condition for Common Roots

  • Condition for both roots common:
  • Coefficients must be strictly proportional.

Apply Proportion

  • Applying the condition to our equations:

Final Ratio

  • Therefore, .
  • Correct Option: 1 : 2 : 3

The Sigma Insight: Common Roots

Solution Diagram

Analyzing the Parabola

Imagine you are standing before the graph of the quadratic equation . If you were to plot this as a function , you would see a beautiful, upward-opening parabola.
To determine its position relative to the -axis, we utilize the discriminant:
By substituting our coefficients—, , —we find:
Because , the parabola never touches the -axis; it floats entirely above it. This confirms that the roots are not real, but rather complex.

The Power of the Conjugate Pair

Now, consider a second equation , where . We are told it shares a common root with our first equation.
Because the first equation has complex roots and the second equation has real coefficients, the Conjugate Pair Theorem applies. This theorem states that if a polynomial with real coefficients has a complex root , it must also have the conjugate as a root.
It is a "package deal." Therefore, if the second equation shares one complex root, it is mathematically forced to share the other as well. Both roots are common.

The Elegance of Proportionality

Once we realize that both equations share the exact same roots, the path forward becomes clear. If two quadratic equations share both roots, they are essentially the same equation, scaled by a constant factor.
This leads us to the condition of proportionality:
This simple, symmetric relationship is the key to the entire problem. By setting these ratios equal, we immediately see that the ratio must be .
It is a stunning example of how a seemingly complex problem about roots collapses into a simple, elegant ratio when you understand the underlying structure. Whenever you see common roots, always check the discriminant first; it is the compass that guides you through the storm of algebra.

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