Sigma Percentile
JEE Main 2020 (7 January Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Sequence and Series: Five numbers are in A.P., whose sum is 25 and product is 2520. If one of these five numbers is , then the greatest number amongst them is

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Visualized Solution

Choosing the Terms of A.P.

  • Let the five numbers in A.P. be:
  • where is the middle term and is the common difference.

Using the Sum Condition

  • Sum of all five terms
  • Notice how the terms cancel out perfectly.

Finding the Middle Term

  • The middle term of the A.P. is .

Setting up the Product Equation

  • Product of all five terms

Substituting

  • Substitute into the product equation:
  • Divide both sides by :

Simplifying the Product

  • Group the terms to use :

Forming a Biquadratic Equation

  • Expand the brackets:
  • Combine like terms:

Factorizing the Equation

  • Let . The equation is .
  • Split the middle term:

Solving for

  • Replacing back with :
  • This gives two possible values for :
  • or

Checking the Given Condition

  • The problem states one of the numbers is .
  • Case 1: If .
  • Terms: . (No here).
  • Case 2: If .
  • Terms for : .
  • Here, is exactly !

Finding the Greatest Number

  • We need the greatest number amongst the five.
  • Greatest number (assuming )
  • Substitute and :
  • Greatest number
  • Greatest number

Final Conclusion

  • The greatest number in the A.P. is .
  • Key Takeaway: Assuming symmetric terms for an odd number of A.P. terms simplifies calculations.

The Sigma Insight: Arithmetic Progression (A.P.)

Solution Diagram

Analyzing the Setup

Imagine you are standing before a complex puzzle. You have five numbers in an Arithmetic Progression (A.P.), their sum is , and their product is .
At first glance, this looks like a system of equations that could spiral into a nightmare of algebra. But here is the secret that separates the novice from the master: the choice of variables.
When dealing with an odd number of terms in an A.P., never start with . Instead, embrace symmetry. By defining our terms as , we place the middle term at the heart of the sequence.
Why does this matter? Because when we sum these terms, the common difference vanishes like magic:
Just like that, we have anchored our middle term at .

The Algebraic Dance

Now that we have , we turn to the product. We are given:
Substituting , we get:
Dividing by , we simplify this to:
Here is where the beauty of algebra shines. If you expand this blindly, you will be lost in a sea of terms. Instead, group the conjugates:
Using the difference of squares identity, , this transforms into:
We have tamed the beast!

The Biquadratic Challenge

Expanding this gives us . Rearranging, we arrive at the biquadratic equation:
Let . We are solving . By splitting the middle term, we find:
This gives us two paths: or .
This is the moment of truth. The problem states one of the numbers is . If , then , and our terms are . No here!
But if , then . Let's test . Our terms become , which simplifies to .
There it is! The term is exactly .

The Final Victory

We have successfully navigated the constraints. The greatest number in our sequence is:
You see, the math didn't just give us an answer; it told a story of symmetry, reduction, and verification. Keep this mindset, and no A.P. problem will ever intimidate you again. The final answer is 16.

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