Sigma Percentile
JEE Advanced 2022
LEVELJEE Main

Animated Solution for Chemistry - s and p-Block Elements: The treatment of galena with produces a gas that is

Select Answer:

* Multiple Correct

Visualized Solution

  • Galena is lead(II) sulfide, .
  • When treated with dilute nitric acid , a vigorous redox reaction occurs.

  • The balanced chemical equation is:

  • Nitric oxide () has a total of valence electrons.
  • Since it has an odd number of electrons, it contains an unpaired electron.
  • Therefore, is paramagnetic.

  • is a diatomic molecule.
  • Any molecule with only two atoms must have a linear geometry.
  • It cannot be bent.

  • is a neutral oxide (along with and ).
  • It is a colorless gas at room temperature.
  • Note: It turns brown when exposed to air due to oxidation to .

  • The gas produced is .
  • It is paramagnetic (Option A).
  • It is colorless (Option D).
  • It is linear (not bent) and neutral (not acidic).

The Sigma Insight: Group 15 Elements

Solution Diagram

The Setup

Galena Meets Nitric Acid
Imagine you are in a chemistry lab, holding a piece of Galena, which is the primary ore of lead, chemically known as lead(II) sulfide ().
You drop this dark, metallic-looking mineral into a test tube containing dilute nitric acid ().
Immediately, a vigorous reaction begins. Nitric acid is a notoriously strong oxidizing agent. It doesn't just dissolve the ore; it actively tears electrons away from the sulfide ions.

The Master Equation

Let's look at the exact chemical equation governing this redox process:
In this reaction, the sulfide ion () is oxidized to elemental sulfur (), which often appears as a pale yellow precipitate.
Simultaneously, the nitrogen in nitric acid is reduced from a oxidation state down to a oxidation state.
This reduction produces a gas that bubbles out of the solution: Nitric Oxide ().

Analyzing the Gas

Nitric Oxide
Now that we have identified the gas as , we need to evaluate its physical and chemical properties to answer the question.
1. Magnetic Nature: To determine if a molecule is paramagnetic or diamagnetic, we count its valence electrons. Nitrogen brings valence electrons, and oxygen brings .
This gives us a total of valence electrons. Because is an odd number, it is mathematically impossible to pair all the electrons up.
There must be at least one unpaired electron. Any molecule with an unpaired electron is strictly paramagnetic.
2. Molecular Geometry: What about its shape? is a diatomic molecule, meaning it consists of exactly two atoms.
Geometrically, the shortest distance between two points is a straight line. Therefore, any diatomic molecule must have a perfectly linear geometry. It is impossible for it to be bent.
3. Chemical Nature and Color: In inorganic chemistry, non-metal oxides are typically acidic. However, there are three classic exceptions that you must memorize: , , and .
These three are neutral oxides. They do not form acids when dissolved in water.
Finally, pure gas is completely colorless.
(Note: If you perform this in an open lab, the colorless will immediately react with oxygen in the air to form , which is a reddish-brown gas. But the itself is colorless!)

Final Conclusion

Bringing all our observations together: the gas produced is .
It is paramagnetic due to its odd number of electrons, and it is a colorless gas.
Therefore, the correct statements are that the gas is paramagnetic and colorless.

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