JEE Main 2021
LEVELJEE Main
Visualized Solution
The Sigma Insight: Group 15 Elements
Analyzing the Setup
Imagine you are in a chemistry lab, and you have two powerful reagents in front of you: phosphorus pentaoxide () and concentrated nitric acid ().
The problem asks us to mix them in a ratio and determine the chemical nature of the resulting nitrogen oxide.
To crack this, we need to understand the personality of our reagents.
Phosphorus pentaoxide is not just any oxide; it is a notoriously aggressive dehydrating agent.
It loves water so much that it will rip hydrogen and oxygen atoms out of other molecules just to form water and hydrate itself!
The Master Equation
When is introduced to , a classic dehydration reaction takes place.
The forces the nitric acid to give up the elements of water.
Let's look at the math of this dehydration.
If we take two molecules of nitric acid () and remove one molecule of water (), what are we left with?
We get , which is nitrogen pentaoxide.
This makes the true anhydride of nitric acid.
The complete balanced chemical equation for this fascinating exchange is:
Here, the absorbs the water to become metaphosphoric acid (), leaving behind the nitrogen pentaoxide gas.
Final Calculation
Now, the spotlight is on .
The question asks for its chemical nature.
Think about the periodic table. Nitrogen is a non-metal.
As a fundamental rule of chemistry, oxides of non-metals are generally acidic.
Furthermore, the oxidation state of nitrogen in is , which is its highest possible oxidation state.
Higher oxidation states in non-metal oxides correspond to stronger acidic character because they have a strong tendency to accept electrons or react with water to release protons.
In fact, if you dissolve in water, it vigorously reacts to give back nitric acid!
This undeniably proves that is an acidic oxide.
Therefore, the chemical nature of the nitrogen oxide compound obtained is acidic, making our correct choice option (a).
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Comprehension Passage
Upon heating in the presence of catalytic amount of , a gas is formed. Excess amount of reacts with white phosphorus to give . The reaction of with pure gives and .
Question 1:
and are, respectively
(A)
and
(B)
and
(C)
and
(D)
and
Question 2:
and are , respectively
(A)
and
(B)
and
(C)
and
(D)
and