Group 15 Elements

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JEE Advanced 2025

The compound(s) with P–H bond(s) is(are)

H_{3} P O_{4}

(B)

H_{3} P O_{3}

(C)

H_{4} P_{2} O_{7}

(D)

H_{3} P O_{2}

JEE Advanced 2025

LEVELJEE Main

The heating of $NH_{4} NO_{2}$ at $60 - 7 0^{\circ} C$ and $NH_{4} NO_{3}$ at $200 - 25 0^{\circ} C$ is associated with the formation of nitrogen containing compounds X and Y, respectively. X and Y, respectively, are

(A)

N_{2}

and

N_{2} O

(B)

NH_{3}

and

NO_{2}

(C)

NO

and

N_{2} O

(D)

N_{2}

and

NH_{3}

JEE Advanced 2017

LEVELJEE Advanced

Comprehension Passage

Upon heating

KClO_{3}

in the presence of catalytic amount of

MnO_{2}

, a gas

W

is formed. Excess amount of

W

reacts with white phosphorus to give

X

. The reaction of

X

with pure

HNO_{3}

gives

Y

and

Z

Question 1:

$W$ and $X$ are, respectively

(A)

O_{3}

and

P_{4} O_{6}

(B)

O_{2}

and

P_{4} O_{10}

(C)

O_{3}

and

P_{4} O_{10}

(D)

O_{2}

and

P_{4} O_{6}

Question 2:

$Y$ and $Z$ are , respectively

(A)

N_{2} O_{4}

and

H_{3} PO_{3}

(B)

N_{2} O_{4}

and

HPO_{3}

(C)

N_{2} O_{5}

and

HPO_{3}

(D)

N_{2} O_{3}

and

H_{3} PO_{4}

JEE Advanced 2023

LEVELJEE Advanced

Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.

List-I

(P)

P_{2} O_{3} + 3 H_{2} O \to

(Q)

P_{4} + 3 NaOH + 3 H_{2} O \to

(R)

PCl_{5} + CH_{3} COOH \to

(S)

H_{3} PO_{2} + 2 H_{2} O + 4 AgNO_{3} \to

List-II

(1)

P(O)(OCH_{3})Cl_{2}

(2)

H_{3} PO_{3}

(3)

PH_{3}

(4)

POCl_{3}

(5)

H_{3} PO_{4}

JEE Advanced 2017

LEVELJEE Main

The order of the oxidation state of the phosphorus atom in $H_{3} PO_{2}$ , $H_{3} PO_{4}$ , $H_{3} PO_{3}$ and $H_{4} P_{2} O_{6}$ is

(A)

H_{3} PO_{4} > H_{4} P_{2} O_{6} > H_{3} PO_{3} > H_{3} PO_{2}

(B)

H_{3} PO_{3} > H_{3} PO_{2} > H_{3} PO_{4} > H_{4} P_{2} O_{6}

(C)

H_{3} PO_{2} > H_{3} PO_{3} > H_{4} P_{2} O_{6} > H_{3} PO_{4}

(D)

H_{3} PO_{4} > H_{3} PO_{2} > H_{3} PO_{3} > H_{4} P_{2} O_{6}

JEE Advanced 2014

LEVELJEE Main

The product formed in the reaction of $SOCl_{2}$ with white phosphorous is

(A)

PCl_{3}

(B)

SO_{2} Cl_{2}

(C)

SCl_{2}

(D)

POCl_{3}

JEE Advanced 2022

LEVELJEE Main

The treatment of galena with $HNO_{3}$ produces a gas that is

* Multiple Correct Options

The nitrogen containing compound produced in the reaction of $HNO_{3}$ with $P_{4} O_{10}$

* Multiple Correct Options

(A)

can also be prepared by reaction of

P_{4}

and

HNO_{3}

(B)

is diamagnetic

(C)

contains one N-N bond

(D)

reacts with Na metal producing a brown gas

JEE Advanced 2018

LEVELJEE Advanced

The total number of compounds having at least one bridging oxo group among the molecules given below is______. $N_{2} O_{3}$ , $N_{2} O_{5}$ , $P_{4} O_{6}$ , $P_{4} O_{7}$ , $H_{4} P_{2} O_{5}$ , $H_{5} P_{3} O_{10}$ , $H_{2} S_{2} O_{3}$ , $H_{2} S_{2} O_{5}$

JEE Advanced 2019

LEVELJEE Main

With reference to aqua regia, choose the correct option(s).

* Multiple Correct Options

(A)

Reaction of gold with aqua regia produces

NO_{2}

in the absence of air

(B)

Aqua regia is prepared by mixing conc.

HCl

and conc.

HNO_{3}

3 : 1

(v/v) ratio

(C)

Reaction of gold with aqua regia produces an anion having

Au

+ 3

oxidation state

(D)

The yellow colour of aqua regia is due to the presence of

NOCl

and

Cl_{2}

JEE Advanced 2021

LEVELJEE Main

The correct statement(s) related to oxoacids of phosphorous is(are)

* Multiple Correct Options

(A)

Upon heating,

H_{3} PO_{3}

undergoes disproportionation reaction to produce

H_{3} PO_{4}

and

PH_{3}

(B)

While

H_{3} PO_{3}

can act as reducing agent,

H_{3} PO_{4}

cannot.

(C)

H_{3} PO_{3}

is a monobasic acid.

(D)

The H atom of P–H bond in

H_{3} PO_{3}

is not ionizable in water.

JEE Advanced 2018

LEVELJEE Main

The compound(s) which generate(s) $N_{2}$ gas upon thermal decomposition below $30 0^{\circ} C$ is (are)

* Multiple Correct Options

(A)

NH_{4} NO_{3}

(B)

(NH_{4})_{2} Cr_{2} O_{7}

(C)

Ba (N_{3})_{2}

(D)

Mg_{3} N_{2}

JEE Advanced 2018

LEVELJEE Main

Based on the compounds of group 15 elements, the correct statement(s) is (are)

* Multiple Correct Options

(A)

Bi_{2} O_{5}

is more basic than

N_{2} O_{5}

(B)

NF_{3}

is more covalent than

BiF_{3}

(C)

PH_{3}

boils at lower temperature than

NH_{3}

(D)

The N–N single bond is stronger than the P–P single bond

JEE Main 2020

LEVELJEE Main

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with $H_{2}$ in the presence of a catalyst gives another gas (C) which is basic in nature. (A) should not be

(A)

NH_{4} NO_{2}

(B)

(NH_{4})_{2} Cr_{2} O_{7}

(C)

NaN_{3}

(D)

Pb (NO_{3})_{2}

JEE Main 2020

LEVELJEE Main

Reaction of ammonia with excess $Cl_{2}$ gives

(A)

NH_{4} Cl

and

N_{2}

(B)

NH_{4} Cl

and

HCl

(C)

NCl_{3}

and

NH_{4} Cl

(D)

NCl_{3}

and

HCl

JEE Main 2019

LEVELJEE Main

Good reducing nature of $H_{3} P O_{2}$ is attributed to the presence of

Which one of the following group-15 hydride is the strongest reducing agent ?

(A)

AsH_{3}

(B)

BiH_{3}

(C)

PH_{3}

(D)

SbH_{3}

JEE Main 2006

LEVELJEE Main

Which of the following statements is true ?

(A)

H_{3} P O_{3}

is a stronger acid than

H_{2} S O_{3}

(B)

In aqueous medium, HF is a stronger acid than HCl

(C)

H C l O_{4}

is weaker acid than

H C l O_{3}

(D)

H N O_{3}

is a stronger acid than

H N O_{2}

JEE Main 2019

LEVELJEE Main

The number of pentagons in $C_{60}$ and trigons (triangles) in white phosphorus, respectively, are

The reaction of zinc with dilute and concentrated nitric acid, respectively, produce

(A)

NO_{2}

and

NO

(B)

NO

and

N_{2} O

(C)

NO_{2}

and

N_{2} O

(D)

N_{2} O

and

NO_{2}

JEE Main 2020

LEVELJEE Main

Aqua-regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this process is

(A)

(B)

N_{2} O_{5}

(C)

N_{2}

(D)

N_{2} O_{3}

LEVELJEE Main

PCl_3 and PCl_5 both exist; NCl_3 exists but NCl_5 does not exist. It is due to

(A)

lower electronegativity of P than N

(B)

lower tendency of N to form covalent bond

(C)

availability of vacant d-orbital in P but not in N

(D)

statement is itself incorrect

LEVELJEE Main

Ammonia forms the complex ion $[C u (N H_{3})_{4}]^{2 +}$ with copper ions in the alkaline solutions but not in acidic solutions. What is the reason for it?

(A)

In acidic solutions, hydration protects copper ions

(B)

In acidic solutions, protons coordinate with ammonia molecules forming

N H_{4}^{+}

ions and

N H_{3}

molecules are not available

(C)

In alkaline solutions, insoluble

C u (O H)_{2}

is precipitated which is soluble in excess of any alkali

(D)

Copper hydroxide is an amphoteric substance

JEE Main 2020

LEVELJEE Main

White phosphorus on reaction with concentrated NaOH solution in an inert atmosphere of $CO_{2}$ gives phosphine and compound (X). (X) on acidification with HCl gives compound (Y). The basicity of compound (Y) is

Statement I: Sodium hydride can be used as an oxidising agent. Statement II: The lone pair of electrons on nitrogen in pyridine makes it basic. Choose the correct answer from the options given below.

(A)

Both statement I and statement II are true

(B)

Both statement I and statement II are false

(C)

Statement I is true but statement II is false

(D)

Statement I is false but statement II is true

The compound(s) with P–H bond(s) is(are)

Comprehension Passage

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } W and X are, respectively

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Y and Z are , respectively

Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.

List-I

List-II

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The order of the oxidation state of the phosphorus atom in H3​PO2​, H3​PO4​, H3​PO3​ and H4​P2​O6​ is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The product formed in the reaction of SOCl2​ with white phosphorous is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The treatment of galena with HNO3​ produces a gas that is

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The nitrogen containing compound produced in the reaction of HNO3​ with P4​O10​

With reference to aqua regia, choose the correct option(s).

The correct statement(s) related to oxoacids of phosphorous is(are)

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The compound(s) which generate(s) N2​ gas upon thermal decomposition below 300∘C is (are)

Based on the compounds of group 15 elements, the correct statement(s) is (are)

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Reaction of ammonia with excess Cl2​ gives

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Good reducing nature of H3​PO2​ is attributed to the presence of

Which one of the following group-15 hydride is the strongest reducing agent ?

Which of the following statements is true ?

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } The number of pentagons in C60​ and trigons (triangles) in white phosphorus, respectively, are

The reaction of zinc with dilute and concentrated nitric acid, respectively, produce

Aqua-regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this process is

PCl_3 and PCl_5 both exist; NCl_3 exists but NCl_5 does not exist. It is due to

.math-text-wrapper .katex { font-size: 1.05em !important; } .math-text-wrapper .katex-display { margin: 1rem 0 !important; } Ammonia forms the complex ion [Cu(NH3​)4​]2+ with copper ions in the alkaline solutions but not in acidic solutions. What is the reason for it?

Statement I: Sodium hydride can be used as an oxidising agent. Statement II: The lone pair of electrons on nitrogen in pyridine makes it basic. Choose the correct answer from the options given below.

$W$ and $X$ are, respectively

$Y$ and $Z$ are , respectively

The order of the oxidation state of the phosphorus atom in $H_{3} PO_{2}$ , $H_{3} PO_{4}$ , $H_{3} PO_{3}$ and $H_{4} P_{2} O_{6}$ is

The product formed in the reaction of $SOCl_{2}$ with white phosphorous is

The treatment of galena with $HNO_{3}$ produces a gas that is

The nitrogen containing compound produced in the reaction of $HNO_{3}$ with $P_{4} O_{10}$

The compound(s) which generate(s) $N_{2}$ gas upon thermal decomposition below $30 0^{\circ} C$ is (are)

Reaction of ammonia with excess $Cl_{2}$ gives

Good reducing nature of $H_{3} P O_{2}$ is attributed to the presence of

The number of pentagons in $C_{60}$ and trigons (triangles) in white phosphorus, respectively, are

Ammonia forms the complex ion $[C u (N H_{3})_{4}]^{2 +}$ with copper ions in the alkaline solutions but not in acidic solutions. What is the reason for it?