Animated Solution for Physics - Atoms and Nuclei: There is a stream of neutrons with a kinetic energy of 0.0327 eV. If the half-life of neutrons is 700 s, what fraction of neutrons will decay before they travel a distance of 10 m?
Visualized Solution
Speed of Neutrons
K=21mv2⟹v=m2K
v=1.675×10−272×0.0327×1.6×10−19
v≈2.5×103 m/s
Time of Flight
t=vd
t=2.5×10310=4.0×10−3 s
Radioactive Decay Law
N=N0e−λt
Decayed neutrons, ΔN=N0−N=N0(1−e−λt)
Fraction decayed=N0ΔN=1−e−λt
Calculating the Fraction
λ=T1/2ln2=7000.693 s−1
Fraction=1−e−λt
For λt≪1,e−λt≈1−λt
Fraction≈λt=(7000.693)×(4.0×10−3)
Fraction≈3.96×10−6
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The Sigma Insight: Radioactivity
Solution Diagram
Have you ever wondered what happens to a neutron when it's not bound inside an atomic nucleus? Free neutrons are actually unstable! They undergo beta decay, transforming into a proton, an electron, and an antineutrino. In this fascinating problem, we are looking at a stream of such free neutrons traveling through space. We need to find out what fraction of them will decay before they cover a distance of 10 m.
Finding the Speed
To understand their journey, we first need to know how fast they are moving
We are given their kinetic energy: K=0.0327 eV.
Before we plug this into our classical kinetic energy formula, we must convert it into the standard SI unit, Joules.
K=0.0327×1.6×10−19 J≈5.23×10−21 J
Now, using the kinetic energy formula K=21mv2, we can solve for the velocity v:
v=m2K
The rest mass of a neutron m is approximately 1.675×10−27 kg. Substituting our values:
v=1.675×10−272×5.23×10−21≈2.5×103 m/s
The Race Against Time
Now that we know they are zipping along at 2.5×103 m/s, how long does it take them to travel the 10 m distance?
Time is simply distance divided by speed:
t=vd=2.5×10310=4.0×10−3 s
This is a mere 4 milliseconds! Given that the half-life of a free neutron is 700 s, this time of flight is incredibly short. We should expect only a minuscule fraction of the neutrons to decay during this brief window.
The Mathematics of Decay
Radioactive decay follows an exponential law
The number of surviving neutrons N after a time t is given by:
N=N0e−λt
We are interested in the fraction of neutrons that have decayed. The number of decayed neutrons is ΔN=N0−N. Therefore, the fraction decayed is:
Fraction=N0N0−N=1−e−λt
The Final Calculation
First, let's find the decay constant λ
It is related to the half-life T1/2 by:
λ=T1/2ln2=7000.693 s−1
Now, we need to evaluate 1−e−λt. Since t=4.0×10−3 s is so much smaller than 700 s, the product λt is extremely close to zero. This allows us to use the brilliant first-order Taylor approximation for the exponential function:
e−x≈1−xfor x≪1
Applying this to our fraction:
Fraction=1−(1−λt)=λt
This beautifully simplifies our calculation! We just need to multiply the decay constant by the time of flight:
Fraction≈(7000.693)×(4.0×10−3)≈3.96×10−6
And there we have it! Only about 4 out of every million neutrons will decay during this 10-meter sprint. It's a beautiful demonstration of how classical kinematics and quantum decay laws intertwine.