Animated Solution for Mathematics - Sequence and Series: Let the harmonic mean and geometric mean of two positive numbers be the ratio 4:5. Then the two number are in the ratio \dots.
Visualized Solution
Geometric Setup of Means
Let the two positive numbers be a and b.
We can represent them as segments on a line.
Geometric Mean (G.M.)
G.M.=ab
Harmonic Mean (H.M.)
H.M.=a+b2ab
The Given Ratio
G.M.H.M.=54
Substitute the Formulas
aba+b2ab=54
Simplify the Expression
a+b2ab=54
Invert the Equation
2aba+b=45
Componendo and Dividendo
If yx=qp, then x−yx+y=p−qp+q
Apply Componendo and Dividendo
a+b−2aba+b+2ab=5−45+4
a+b−2aba+b+2ab=9
Recognize Perfect Squares
(a−b)2(a+b)2=9
Take the Square Root
a−ba+b=3
Solve for ba
a+b=3a−3b
4b=2a
ba=2
Final Ratio
Squaring both sides: ba=4
Ratio a:b=4:1
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The Sigma Insight: Relation Between A.M., G.M., and H.M.
Solution Diagram
Analyzing the Setup
When we discuss the Harmonic Mean (H.M.) and the Geometric Mean (G.M.), we are exploring fundamental pillars of mathematical analysis. For two positive numbers a and b, these means are defined as:
G.M.=ab
H.M.=a+b2ab
These values are not merely abstract formulas; they represent deep geometric relationships. They are two sides of the same coin, linked by the properties of segments on a line.
The Algebraic Bridge
Our problem provides the ratio of the Harmonic Mean to the Geometric Mean as 4:5. Mathematically, we express this as:
G.M.H.M.=54
Substituting the definitions into this ratio, we obtain:
aba+b2ab=54
By simplifying the expression through the cancellation of the common factor ab, we arrive at a more manageable form:
a+b2ab=54
The Power of Componendo and Dividendo
To solve for the ratio a:b, we first invert the equation to isolate the structure of a perfect square:
2aba+b=45
We now apply the rule of Componendo and Dividendo, which states that if yx=qp, then x−yx+y=p−qp+q. Applying this to our equation:
a+b−2aba+b+2ab=5−45+4
This simplifies elegantly to:
(a−b)2(a+b)2=9
The Final Reveal
Taking the square root of both sides of the equation, we obtain:
a−ba+b=3
Cross-multiplying to solve for the relationship between a and b yields: