Sigma Percentile
JEE Main 2023 (15 Apr Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Sequence and Series: Let and be two arithmetic means and and be three geometric means of two distinct positive numbers. Then is equal to

Select Answer:

Visualized Solution

Define the Extremes and

  • Let the two distinct positive numbers be and .

Insert Arithmetic Means

  • and are two arithmetic means between and .
  • The sequence forms an A.P.

Property of Arithmetic Means

  • In an A.P., the sum of means equals the sum of the extremes.

Insert Geometric Means

  • are three geometric means between and .
  • The sequence forms a G.P.

Common Ratio of the G.P.

  • Let be the common ratio of this G.P.
  • The total number of terms is .
  • The term is .

Expressing

Calculate and

Calculate

Calculate and

Substitute into the Expression

  • Expression
  • Substitute the calculated values:

Simplify the Expression

  • Combine like terms:

Factorize the Expression

  • Factor out :
  • Recognize the algebraic identity:

Final Substitution

  • Recall from Step 2:
  • Recall from Step 8:
  • Substitute these back into :

Conclusion

  • The value of is .
  • Comparing with the given options, this matches Option 1.

The Sigma Insight: Relation Between A.M., G.M., and H.M.

Solution Diagram

Analyzing the Setup

Imagine you are standing on a number line, holding two distinct positive numbers, and . These are our anchors, our extremes.
Between them, we are tasked with inserting two arithmetic means, and , and three geometric means, , and . This problem is not just about calculation; it is about uncovering the hidden symmetry between arithmetic and geometric progressions.

The Arithmetic Foundation

First, let us look at the arithmetic side. When we insert and between and , we create an Arithmetic Progression: .
The beauty of an A.P. lies in its linearity. The sum of the means is always equal to the sum of the extremes.
Thus, we immediately find that:
Keep this relationship safe in your mind; it is the key to our final destination.

The Geometric Dance

Now, let us pivot to the geometric side. We have inserted between and , forming a Geometric Progression: .
Let be the common ratio. Since there are five terms in total, the fifth term is , which gives us:
Now, we express our means: , , and . The expression we need to evaluate is .
Let us calculate these powers:
Finally, the term is simply . Since , we find that:

The Algebraic Synthesis

We are now ready to assemble our masterpiece. Substituting these values into our expression , we get:
Combining the like terms, we arrive at:
Look closely at this expression. If we factor out , we are left with . The term inside the parenthesis is a perfect square, .
So, the expression simplifies to:
Now, recall our earlier findings: and . Substituting these back, we get:
This is the elegance of mathematics—a complex-looking expression collapsing into a simple, beautiful identity. You have successfully navigated the relationship between means and extremes.

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Comprehension Passage

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Which one of the following statements is correct ?

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Which one of the following statements is correct ?

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Which one of the following statements is correct?

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