The Sigma Insight: Fundamental Theorem & Properties of Definite Integrals
Solution Diagram
Analyzing the Setup
We are tasked with evaluating the integral:
I=π2∫π/65π/6(8[cscx]−5[cotx])dx
By the linearity of the integral, we can decompose this into two distinct parts:
I=π16∫π/65π/6[cscx]dx−π10∫π/65π/6[cotx]dx
Let us define these as I1 and I2 respectively.
Phase 1
The Cosecant Mystery
Consider the function f(x)=cscx on the interval (6π,65π). At the boundaries, csc(6π)=2 and csc(65π)=2.
However, between these points, the function dips, reaching its minimum value of 1 at x=2π. Thus, for all x in our open interval, 1≤cscx<2.
Because the function never reaches 2 inside this interval, the greatest integer [cscx] is simply 1. The integral I1 becomes:
I1=∫π/65π/61dx=65π−6π=64π=32π
Phase 2
The Cotangent Odyssey
Now, we turn to I2=∫π/65π/6[cotx]dx. The cotangent function is strictly decreasing on this interval.
At x=6π, cotx=3≈1.732. At x=65π, cotx=−3≈−1.732.
As it descends, it crosses the integers 1,0,−1. We split the integral at the points where cotx equals these integers:
1. cotx=1⇒x=4π
2. cotx=0⇒x=2π
3. cotx=−1⇒x=43π
This divides our interval into four sub-intervals where the greatest integer is constant:
- [6π,4π)⇒[cotx]=1
- [4π,2π)⇒[cotx]=0
- [2π,43π)⇒[cotx]=−1
- [43π,65π]⇒[cotx]=−2