Analyzing the Setup
We are tasked with evaluating the integral:
I=∫−π/2π/2[x]+[sinx]+4dx
The presence of the Greatest Integer Function (GIF) symbols [x] and [sinx] indicates that the integrand is a piecewise constant function. To solve this, we must identify the points of discontinuity within the domain [−π/2,π/2]≈[−1.57,1.57].
The function [x] jumps at integers −1,0, and 1. The function [sinx] jumps when sinx equals an integer, which occurs at x=−π/2,0, and π/2. Combining these, we partition the domain into four distinct intervals: [−π/2,−1), [−1,0), [0,1), and [1,π/2).
Walking the Intervals
We evaluate the integral across each identified interval:
1. Interval [−π/2,−1):
Here,
[x]=−2 and
[sinx]=−1. The denominator is
−2−1+4=1.
I1=∫−π/2−11dx=−1−(−π/2)=2π−1
2. Interval [−1,0):
Here,
[x]=−1 and
[sinx]=−1. The denominator is
−1−1+4=2.
I2=∫−1021dx=21(0−(−1))=21
3. Interval [0,1):
Here,
[x]=0 and
[sinx]=0. The denominator is
0+0+4=4.
I3=∫0141dx=41(1−0)=41
4. Interval [1,π/2):
Here,
[x]=1 and
[sinx]=0. The denominator is
1+0+4=5.
I4=∫1π/251dx=51(2π−1)=10π−51
The Grand Summation
To find the total value of the integral, we sum the results from each interval:
I=(2π−1)+21+41+(10π−51)
Grouping the terms involving π and the constant terms:
Sum of π terms: π(21+101)=π(106)=53π
Sum of constants: −1+21+41−51=20−20+10+5−4=−209
Combining these, we obtain the final result:
I=53π−209=2012π−9=203(4π−3)