Sigma Percentile
JEE Main 2019 (10 January)
LEVELJEE Main

Animated Solution for Mathematics - Definite Integration: The value of , where denotes the greatest integer less than or equal to , is :

Select Answer:

Visualized Solution

The Integral Setup

  • Given integral:
  • The function involves the Greatest Integer Function .
  • is a piecewise constant function, meaning it jumps at integer values.

Identifying Critical Points

  • Critical points for in : .
  • Critical points for : .
  • Combined sub-intervals: .

Interval 1:

  • For :
  • (since )
  • Denominator:
  • Integral

Interval 2:

  • For :
  • (since )
  • Denominator:
  • Integral

Interval 3:

  • For :
  • (since )
  • Denominator:
  • Integral

Interval 4:

  • For :
  • (since )
  • Denominator:
  • Integral

Summing the Parts

  • Total Integral
  • We need to add these four areas together.

Grouping Terms

  • Group terms:
  • Group constant terms:
  • Common denominator for constants is :

Final Simplification

  • Take common denominator :
  • Factor out :
  • This matches Option (4).

The Sigma Insight: Fundamental Theorem & Properties of Definite Integrals

Solution Diagram

Analyzing the Setup

We are tasked with evaluating the integral:
The presence of the Greatest Integer Function (GIF) symbols and indicates that the integrand is a piecewise constant function. To solve this, we must identify the points of discontinuity within the domain .
The function jumps at integers and . The function jumps when equals an integer, which occurs at and . Combining these, we partition the domain into four distinct intervals: , , , and .

Walking the Intervals

We evaluate the integral across each identified interval:
1. Interval : Here, and . The denominator is .
2. Interval : Here, and . The denominator is .
3. Interval : Here, and . The denominator is .
4. Interval : Here, and . The denominator is .

The Grand Summation

To find the total value of the integral, we sum the results from each interval:
Grouping the terms involving and the constant terms:
Combining these, we obtain the final result:

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