Sigma Percentile
JEE Main 2024 (30 Jan Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Definite Integration: The value , where denotes the greatest integer less than or equal to , is _____

Enter Numerical Value:

Visualized Solution

Understanding the Integral

  • Given integral:
  • denotes the Greatest Integer Function (GIF).
  • Strategy: Break the integral at points where the inner function becomes an integer.

Defining the Inner Function

  • Let
  • At lower limit ,
  • At upper limit ,
  • The function increases from to .

Finding Critical Point:

  • We need to find where crosses integer values.
  • Set
  • Squaring both sides:

Solving for First Breakpoint

  • So, for , .

Finding Critical Point:

  • Next integer is .
  • Set
  • Squaring both sides:

Solving for Second Breakpoint

  • So, for , .

The Upper Limit

  • We already know at , .
  • So, for , .
  • The integral breaks into three distinct regions.

Breaking the Integral

  • The first integral evaluates to zero.

Evaluating the Intervals

Arithmetic Simplification

  • Simplify the first bracket:
  • Simplify the second bracket:

Final Calculation of

  • Distribute the :

The Sigma Insight: Fundamental Theorem & Properties of Definite Integrals

Solution Diagram

Analyzing the Setup

The Greatest Integer Function (GIF), denoted by , acts like a staircase. Instead of attempting a complex integration, we identify the points where the function jumps between integer values.
As increases from to , the function climbs monotonically from to . Because the function is continuous and increasing, it must pass through the integer values and .

Finding the Jump Points

To determine the intervals where the GIF remains constant, we solve for the values of where the function hits these integers.
For the first jump, we set the function equal to :
Squaring both sides yields:
For the second jump, we set the function equal to :
Squaring both sides yields:

Evaluating the Integral

We now partition the interval based on these jump points to evaluate the integral :
1. On the interval , the function value is between and , so the GIF is . 2. On the interval , the function value is between and , so the GIF is . 3. On the interval , the function value is between and , so the GIF is .
The integral becomes the sum of three distinct areas:

Final Calculation

Calculating the lengths of these intervals: - The first part is . - The second part is . - The third part is .
Summing these values and multiplying by the external factor of :
The final result is .

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