Analyzing the Setup
In the realm of 3D geometry, reflecting a point
P(a,6,9) across a line
L defined by
7x−3=5y−2=−9z−1
results in an image point
Q(20,b,−a−9). This process relies on the principle of symmetry, where the line
L acts as the perpendicular bisector of the segment
PQ.
The Midpoint
Our Anchor in the Void
The midpoint M of the segment PQ must lie on the line L. We calculate the coordinates of M by averaging the coordinates of P and Q:
M=(2a+20,26+b,29+(−a−9))
Simplifying the components, we obtain:
Since M lies on the line L, it must satisfy the given symmetric equations of the line.
The Algebraic Bridge
Substituting the coordinates of M into the line equation, we get:
72a+20−3=52b+6−2=−9−2a−1
Simplifying the numerators, the expression becomes:
Solving the Mystery
To determine the value of a, we equate the first and third ratios:
Cross-multiplying and simplifying, we have 18(a+14)=14(a+2), which reduces to 9(a+14)=7(a+2). Expanding this yields 9a+126=7a+14, leading to 2a=−112, or a=−56.
Next, we solve for b by equating the first and second ratios:
14−56+14=10b+2⟹−3=10b+2
This results in b+2=−30, which gives b=−32.
The Final Calculation
With the values of a and b determined, we calculate the final required value:
∣a+b∣=∣−56+(−32)∣=∣−88∣=88
Through the application of geometric symmetry and algebraic substitution, we have successfully resolved the coordinates and reached the final result of 88.