Sigma Percentile
JEE Main 2020 - 5 Sep (Morning)
LEVELJEE Main

Animated Solution for Mathematics - Three Dimensional Geometry: If is the image of the point in the line , then is equal to:

Select Answer:

Visualized Solution

and Line

  • Given point:
  • Given line :
  • Goal: Find the image and calculate .

The Foot of Perpendicular

  • To find the image , we first need the foot of the perpendicular on line .

General Point

  • Let
  • General point

Vector

Perpendicularity Condition

  • Direction vector of is
  • Since , their dot product is zero:

Setting up the Dot Product

  • Equation:

Solving for

  • Simplify:
  • Result:

Exact Coordinates of

  • Substitute into
  • Result:

Midpoint Relation

  • Let the image be .
  • is the exact midpoint of segment .

Midpoint Formula

Finding

  • Image

Final Calculation

  • We need .
  • The correct answer is 2.

The Sigma Insight: Equation of a Line in Space

Solution Diagram

The Mirror in 3D Space

A Journey of Reflection
Imagine you are standing in a room, holding a point in your hand. Before you lies a mirror, but this mirror is not a flat surface—it is a straight line defined by the equation:
Your goal is to find the reflection of point on the other side of this line. This is not just a calculation; it is a beautiful dance of vectors and symmetry.

Phase 1

The Stepping Stone
To find the image , we cannot simply jump across the line. We need a bridge. That bridge is the foot of the perpendicular, .
If we drop a perpendicular from onto the line , the point where it hits, , is the exact midpoint between and its image . Think of as the anchor point that holds the symmetry together.

Phase 2

The Parametric Power
Since lies on the line , we can describe its position using a single parameter, . By setting the line equation equal to , we can express any point on the line as:
This is the power of parametric form—it turns a 3D line into a simple 1D path.

Phase 3

The Perpendicularity Condition
Now, we construct the vector by subtracting the coordinates of from :
We know that must be perpendicular to the line . The direction vector of is .
Because they are perpendicular, their dot product must be zero: . This gives us the equation:
Solving this, we find , which simplifies to , or .

Phase 4

The Final Symmetry
With , we find the exact coordinates of by substituting back into our general point:
Now, we use the midpoint formula: . This implies:
Solving these gives . The image point is .
Finally, the sum . You have successfully navigated the mirror of 3D space!

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