Sigma Percentile
JEE Main 2019 (09 April Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Sets and Relations: For any two statements p and q, the negation of the expression is

Select Answer:

Visualized Solution

Visualizing the Logic Stage

  • Given expression:
  • Objective: Find the negation

Identifying the Inner Term

  • Inner term:
  • This represents the region in that is outside .

Adding Set

  • The expression is .
  • We need to union the green region with set .

Simplifying the Union

  • The combined shaded region is simply the union of and .

Applying the Negation

  • We need the negation:
  • Visually, this is the region outside both circles.

Visual Conclusion

  • The red region represents .

Algebraic Proof: Setup

  • Expression to negate:
  • We will use De Morgan's Laws.

First Application of De Morgan's Law

  • Apply De Morgan's Law to the outer negation:
  • Result:

Second Application of De Morgan's Law

  • Apply De Morgan's Law to the inner term:
  • Result:

Distributive Law

  • Distribute across the OR:

Complement Law

  • A statement AND its negation is always False:
  • Result:

Identity Law and Final Answer

  • False OR any statement is the statement itself:
  • Final Answer:

The Sigma Insight: Types of Sets and Set Operations

Solution Diagram

The Elegance of Logical Negation

Welcome, future engineers! Today, we are diving into the beautiful, structured world of symbolic logic. Often, students view logic as a dry, mechanical set of rules, but I want you to see it as the very foundation of the digital universe.
Every line of code, every circuit in your smartphone, and every algorithm powering the AI you use is built on these fundamental logical operations. Today, we are going to dismantle the expression and rebuild it, piece by piece, until its simplicity is revealed.

Phase 1

The Visual Intuition
Before we touch a single algebraic symbol, let us train our minds to see the geometry of logic. Imagine a large rectangle representing our universal set of possibilities. Inside, we have two circles, and .
The expression is our starting point. Let us break it down. The term is the region inside that is strictly outside . If you shade this, you get a crescent shape.
Now, the expression asks for the union of this crescent with the entire set . When you combine the blue circle of with the green crescent of , you have effectively filled both circles entirely!
This means our complex expression simplifies beautifully to just . But wait, the question asks for the negation of this entire expression. The negation of is everything outside both circles.
Visually, this is the region where neither nor exists, which is . We have our answer, but let us prove it with the rigor of algebra.

Phase 2

The Algebraic Rigor
Now, let us translate our visual intuition into the language of symbols. We start with the expression .
To negate this, we must use De Morgan's Laws. Think of De Morgan's as the 'distributive property' for logic, but with a twist: it flips the operators.
When we apply the outer negation, the OR symbol becomes an AND symbol , and the negation distributes to both terms. This gives us:
Now, we apply De Morgan's again to the inner bracket. The double negation of becomes , the AND symbol becomes an OR symbol , and becomes . Our expression now stands as:

Phase 3

The Beauty of Simplification
We are almost there. Now, we use the Distributive Law to expand our expression:
Look closely at that first term, . This is the Complement Law in action. A statement cannot be true and false at the same time; therefore, is always False.
Our expression simplifies to . Finally, we apply the Identity Law: False OR any statement is simply the statement itself.
The False term vanishes, leaving us with the elegant result: . Whether you look at it through the lens of a Venn diagram or the rigor of algebraic laws, the truth remains the same.

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