Sigma Percentile
JEE Main 2020
LEVELJEE Main

Animated Solution for Chemistry - Organic Chemistry: A solution of -chloroaniline, -chlorophenol and -chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of to give fraction A. The left over organic phase was extracted with dilute solution to give fraction B. The final organic layer was labelled as fraction C. Fractions A, B and C contain respectively

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Visualized Solution

Acid-Base Extraction

  • Mixture: -chloroaniline, -chlorophenol, -chlorobenzoic acid

Acidity Order

  • Acidity: Carboxylic acid Phenol Amine (Base)

Extraction with

  • is a weak base.
  • It reacts only with strong acids.

Fraction A

  • -chlorobenzoic acid + Sodium -chlorobenzoate (aq)

Remaining Organic Layer

  • Organic layer contains -chloroaniline and -chlorophenol.

Extraction with

  • is a strong base.
  • It reacts with weak acids like phenols.

Fraction B

  • -chlorophenol + Sodium -chlorophenoxide (aq)

Fraction C

  • -chloroaniline remains unreacted in the organic layer.

Final Conclusion

  • A: -chlorobenzoic acid
  • B: -chlorophenol
  • C: -chloroaniline

The Sigma Insight: Nomenclature and Characterisation

Solution Diagram

The Art of Separation

Imagine you are handed a flask containing a mixture of three different organic compounds dissolved in ethyl acetate.
Your mission is to separate them cleanly.
How do we achieve this? We use a powerful technique called acid-base extraction.
This method relies on a simple principle: converting water-insoluble organic compounds into water-soluble ionic salts.

Analyzing the Acidity

Before we start adding reagents, we must understand the chemical nature of our mixture.
We have -chlorobenzoic acid, -chlorophenol, and -chloroaniline.
Let's look at their acidic strengths.
-chlorobenzoic acid is a carboxylic acid, making it the strongest acid in our mixture.
-chlorophenol is a phenol, which is a weak acid.
Finally, -chloroaniline is an amine, which is actually a base.

The First Extraction

Fraction A
Our first step is to add a saturated solution of (sodium bicarbonate).
Sodium bicarbonate is a weak base.
Because it is weak, it can only react with strong acids.
Therefore, it will only deprotonate the -chlorobenzoic acid.
The resulting sodium -chlorobenzoate is an ionic salt, which is highly soluble in water.
It moves into the aqueous layer, which we collect as Fraction A.

The Second Extraction

Fraction B
Now, we are left with an organic layer containing -chlorophenol and -chloroaniline.
To separate these, we add a dilute solution of (sodium hydroxide).
Sodium hydroxide is a strong base.
It is powerful enough to deprotonate the weak acid, -chlorophenol.
The newly formed sodium -chlorophenoxide dissolves in the aqueous layer.
We collect this aqueous layer as Fraction B.

The Final Layer

Fraction C
What remains in our ethyl acetate organic layer?
Only the -chloroaniline is left behind.
Since it is a base, it does not react with the basic solution.
It remains completely un-ionized and stays dissolved in the organic solvent.
This final organic layer is our Fraction C.

Final Conclusion

By strategically using bases of different strengths, we successfully separated the mixture.
Fraction A contains -chlorobenzoic acid.
Fraction B contains -chlorophenol.
Fraction C contains -chloroaniline.
Therefore, the correct option is (c).

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