The Art of Separation
Imagine you are handed a flask containing a mixture of three different organic compounds dissolved in ethyl acetate.
Your mission is to separate them cleanly.
How do we achieve this? We use a powerful technique called acid-base extraction.
This method relies on a simple principle: converting water-insoluble organic compounds into water-soluble ionic salts.
Analyzing the Acidity
Before we start adding reagents, we must understand the chemical nature of our mixture.
We have m-chlorobenzoic acid, m-chlorophenol, and m-chloroaniline.
Let's look at their acidic strengths.
m-chlorobenzoic acid is a carboxylic acid, making it the strongest acid in our mixture.
m-chlorophenol is a phenol, which is a weak acid.
Finally, m-chloroaniline is an amine, which is actually a base.
The First Extraction
Fraction A
Our first step is to add a saturated solution of NaHCO3ā (sodium bicarbonate).
Sodium bicarbonate is a weak base.
Because it is weak, it can only react with strong acids.
Therefore, it will only deprotonate the m-chlorobenzoic acid.
m-chlorobenzoic acid+NaHCO3āāSodium m-chlorobenzoate+H2āO+CO2ā
The resulting sodium m-chlorobenzoate is an ionic salt, which is highly soluble in water.
It moves into the aqueous layer, which we collect as Fraction A.
The Second Extraction
Fraction B
Now, we are left with an organic layer containing m-chlorophenol and m-chloroaniline.
To separate these, we add a dilute solution of NaOH (sodium hydroxide).
Sodium hydroxide is a strong base.
It is powerful enough to deprotonate the weak acid, m-chlorophenol.
m-chlorophenol+NaOHāSodium m-chlorophenoxide+H2āO
The newly formed sodium m-chlorophenoxide dissolves in the aqueous layer.
We collect this aqueous layer as Fraction B.
The Final Layer
Fraction C
What remains in our ethyl acetate organic layer?
Only the m-chloroaniline is left behind.
Since it is a base, it does not react with the basic NaOH solution.
It remains completely un-ionized and stays dissolved in the organic solvent.
This final organic layer is our Fraction C.
Final Conclusion
By strategically using bases of different strengths, we successfully separated the mixture.
Fraction A contains m-chlorobenzoic acid.
Fraction B contains m-chlorophenol.
Fraction C contains m-chloroaniline.
Therefore, the correct option is (c).