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Animated Solution for Chemistry - Organic Chemistry: Which type of isomerism is shown by 2, 3-dichlorobutane?

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Visualized Solution

Structure of 2,3-dichlorobutane

  • The chemical structure of 2,3-dichlorobutane is .

Identifying Chiral Centers

  • A chiral carbon () is an asymmetric carbon atom attached to four different types of atoms or groups.
  • Carbon-2 is attached to: , , , and .
  • Carbon-3 is attached to: , , , and .

Conclusion

  • Since the molecule possesses two chiral carbon atoms, it can exist as non-superimposable mirror images.
  • Thus, it exhibits optical isomerism.

The Sigma Insight: Nomenclature and Characterisation

Solution Diagram
The problem asks us to identify the type of isomerism exhibited by 2,3-dichlorobutane. To solve this, we need to systematically analyze the structure of the molecule and check the conditions for different types of isomerism.

Analyzing the Setup

Let's start by visualizing the molecule given to us. The name "butane" indicates a straight chain of four carbon atoms. The "2,3-dichloro" part tells us that there are chlorine atoms attached to the second and third carbon atoms in this chain.
When we draw the expanded structural formula, we get:
Right away, we can rule out a few options. Geometric isomerism requires restricted rotation, which typically happens around a carbon-carbon double bond or within a rigid ring structure. Since 2,3-dichlorobutane is an open-chain alkane with only single bonds, there is free rotation around all carbon-carbon bonds. Thus, it cannot show geometric isomerism.

Identifying Chiral Centers

Now, let's investigate the possibility of optical isomerism. The fundamental requirement for a molecule to show optical isomerism is the presence of chirality. A carbon atom is considered chiral (or asymmetric) if it is hybridized and bonded to four completely different atoms or groups of atoms.
Let's look closely at the second carbon atom (C-2). What is it attached to? 1. A hydrogen atom () 2. A chlorine atom () 3. A methyl group () 4. The rest of the carbon chain ()
Since all four of these groups are different, C-2 is a chiral center! We usually mark this with an asterisk ().
If we apply the exact same logic to the third carbon atom (C-3), we find that it is also attached to the same four distinct groups. Therefore, C-3 is our second chiral center.

The Final Verdict

Because 2,3-dichlorobutane possesses chiral carbon atoms, the molecule can exist in different spatial arrangements that are non-superimposable mirror images of each other (known as enantiomers).
Molecules that have non-superimposable mirror images are optically active; they can rotate the plane of plane-polarized light. Therefore, the presence of these chiral centers confirms that 2,3-dichlorobutane exhibits optical isomerism.
(Note: Because the two chiral centers are identical in terms of the groups attached to them, this molecule also has an optically inactive meso form due to an internal plane of symmetry. However, the molecule as a whole is classified as showing optical isomerism.)

Similar Questions

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