The Golden Rules of IUPAC Nomenclature
When tackling any IUPAC nomenclature problem, you must follow a strict hierarchy of rules.
First, identify the principal functional group. This group dictates the suffix of the parent chain and holds the highest priority for numbering.
Second, select the longest continuous carbon chain that contains this principal functional group.
Finally, number the carbon chain such that the principal functional group receives the lowest possible locant (number). Only after satisfying this rule do we consider the locants for other substituents like alkyl groups or halogens.
Analyzing the Options
The Correct Names
Let's evaluate the first three options to see how these rules are applied correctly.
In option (a), the molecule is CH3CH2CH2C(=O)OC2H5. The functional group here is an ester. The alkyl group attached to the oxygen is an ethyl group. The main chain, including the carbonyl carbon, consists of four carbon atoms, making it a butanoate. Combining these parts gives us ethyl butanoate, which is perfectly correct.
Moving to option (b), we have CH3CH(CH3)CH2CHO. The principal functional group is an aldehyde (−CHO). According to IUPAC rules, the aldehyde carbon is always designated as carbon-1. The longest chain is four carbons long (butanal), and there is a methyl substituent at carbon-3. Thus, the name 3-methylbutanal is correct.
In option (c), the structure is CH3CH(CH3)C(=O)CH2CH3. The functional group is a ketone. The longest chain has five carbons. If we number from left to right, the ketone is at position 3, and the methyl group is at position 2. Numbering from right to left also puts the ketone at position 3, but the methyl group would be at position 4. To give the substituent the lower number, we must number from left to right. Therefore, the name 2-methylpentan-3-one (or 2-methyl-3-pentanone) is correct.
The Trap
Spotting the Incorrect Name
Now, let's examine option (d), which is CH3CH(OH)CH(CH3)CH3.
The principal functional group here is the alcohol (−OH). The longest carbon chain contains four carbons.
To give the −OH group the lowest possible number, we must number the chain from left to right. This assigns position 2 to the −OH group and position 3 to the methyl group.
Therefore, the correct IUPAC name is 3-methylbutan-2-ol.
However, the option provides the name 2-methyl-3-butanol. This name is derived by numbering the chain from right to left, which incorrectly gives the principal functional group a higher locant (3 instead of 2). This is a classic violation of the lowest locant rule!
Final Conclusion
By systematically applying the IUPAC rules, we can confidently identify that option (d) contains the incorrect nomenclature. Always remember that the principal functional group is the highest priority—it must always receive the lowest possible number, even if it means assigning higher numbers to other substituents.