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JEE Main 2007
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Animated Solution for Physics - Optics: Two lenses of power and are in contact with each other. The focal length of the combination is

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Visualized Solution

  • Given two lenses in contact:
  • (Concave)
  • (Convex)

  • Equivalent power of lenses in contact:

  • Relation between focal length and power:

  • The focal length of the combination is .

The Sigma Insight: Lens

Solution Diagram
Imagine two people pushing a heavy box. One pushes forward with a force of 5 units, and the other pushes backward with a force of 15 units. What happens? The box moves backward with a net force of 10 units. Lenses in contact work in a very similar way!

The Power of Lenses

In optics, the power of a lens tells us how strongly it converges or diverges light. A positive power means the lens converges light (like a magnifying glass), while a negative power means it diverges light. The unit of power is the Diopter (D).
In our problem, we have two lenses: 1. A concave lens with a power of . 2. A convex lens with a power of .

Combining Forces

When thin lenses are placed right next to each other (in contact), they act together as a single, new lens. The beautiful part? The power of this new "equivalent" lens is simply the algebraic sum of the individual powers.
Let's plug in our numbers:
The net power is . The negative sign is a huge clue—it tells us that the combination behaves like a concave (diverging) lens!

Finding the Focal Length

Now that we know the equivalent power, finding the focal length is a breeze. Power and focal length are inversely related. The formula is:
Since our options are in centimeters, it's easier to use the modified formula:
Substituting our equivalent power:
And there we have it! The focal length of the combination is . It's a straightforward application of the power addition rule, but it's a fundamental concept that appears everywhere in optics.

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