Animated Solution for Chemistry - s and p-Block Elements: Two elements A and B have similar chemical properties. They don't form solid hydrogencarbonates, but react with nitrogen to form nitrides. A and B, respectively, are
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Visualized Solution
A and B Properties
\text{Property 1: Do not form solid } HCO_3^-
\text{Property 2: React with } N_2 \text{ to form nitrides}
\text{Similarity in properties between elements of 2nd and 3rd periods.}
\text{Due to similar polarizing power } (\phi \propto \frac{\text{charge}}{\text{radius}^2})
Visualizing the Link
\text{Diagonal Pairs:}
Li \leftrightarrow Mg
Be \leftrightarrow Al
B \leftrightarrow Si
Final Answer
\text{Elements } A \text{ and } B \text{ are } Li \text{ and } Mg.
\text{Correct Option: (d)}
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The Sigma Insight: Alkali Metals
Solution Diagram
Decoding the Chemical Clues
Imagine you are a chemical detective, and the problem has just handed you two crucial pieces of evidence about two mystery elements, A and B.
First, they refuse to form solid hydrogencarbonates (also known as bicarbonates). Second, they have a special affinity for nitrogen, reacting directly with N2 gas to form solid nitrides.
To crack this case, we need to scan the periodic table and see which groups exhibit these specific behaviors.
The Group 2 Suspects
Let's start by interrogating the Group 2 elements, the alkaline earth metals like Magnesium (Mg) and Calcium (Ca).
These metals are known to be quite reactive with nitrogen upon heating. The reaction proceeds as follows:
3M+N2ΔM3N2
Furthermore, the bicarbonates of Group 2 metals are notoriously unstable in the solid state. If you try to evaporate the water from an aqueous solution of Mg(HCO3)2, it decomposes into magnesium carbonate, water, and carbon dioxide. They only exist happily in an aqueous solution:
MCO3(s)+CO2(g)+H2O(l)→M(HCO3)2(aq)
So, it is highly probable that one of our mystery elements belongs to Group 2.
The Group 1 Rebel
Now, let's look at Group 1, the alkali metals. Generally, metals like Sodium (Na) and Potassium (K) do not react directly with nitrogen gas.
Additionally, they form very stable solid bicarbonates. Think of baking soda, which is solid NaHCO3. Based on this, Group 1 metals should be ruled out.
But wait! There is a famous rebel in Group 1: Lithium (Li).
Because Lithium is exceptionally small, its cation Li+ has a very high charge density and polarizing power. This allows it to form a stable lattice with the highly charged nitride ion (N3−):
6Li+N2Δ2Li3N
Similarly, this high polarizing power distorts the large bicarbonate ion (HCO3−) so severely that solid LiHCO3 cannot exist; it decomposes upon attempted isolation. Lithium perfectly matches our clues!
The Diagonal Relationship
Why does Lithium, a Group 1 metal, behave so much like Magnesium, a Group 2 metal?
This is a beautiful manifestation of the diagonal relationship in the periodic table. As you move across a period from left to right, atomic size decreases and nuclear charge increases. As you move down a group, atomic size increases.
When you move diagonally (one step right and one step down), these two opposing effects roughly cancel each other out. This results in elements with very similar ionic potentials (charge-to-size ratios).
Because Li+ and Mg2+ have similar polarizing power, they exhibit strikingly similar chemical properties. They both form nitrides, and neither forms a solid bicarbonate.
Therefore, our mystery elements A and B are Lithium (Li) and Magnesium (Mg).