Sigma Percentile
JEE Main 2020
LEVELJEE Main

Animated Solution for Chemistry - s and p-Block Elements: Two elements and have similar chemical properties. They don't form solid hydrogencarbonates, but react with nitrogen to form nitrides. and , respectively, are

Select Answer:

Visualized Solution

and Properties

  • \text{Property 1: Do not form solid } HCO_3^-
  • \text{Property 2: React with } N_2 \text{ to form nitrides}

Group 2 Metals

  • \text{Group 2 Metals (Mg, Ca, Sr, Ba):}
  • 3M + N_2 \xrightarrow{\Delta} M_3N_2
  • MCO_3(s) + CO_2(g) + H_2O(l) \rightarrow M(HCO_3)_2(aq)

Group 1 Metals

  • \text{Group 1 Metals (Na, K, Rb, Cs):}
  • \text{Do NOT form nitrides directly.}
  • \text{Form stable solid bicarbonates (e.g., } NaHCO_3 \text{)}

Lithium's Anomaly

  • \text{Exception: Lithium (Li)}
  • 6Li + N_2 \xrightarrow{\Delta} 2Li_3N
  • LiHCO_3 \text{ does not exist as a solid.}

Diagonal Relationship

  • \text{Diagonal Relationship:}
  • \text{Similarity in properties between elements of 2nd and 3rd periods.}
  • \text{Due to similar polarizing power } (\phi \propto \frac{\text{charge}}{\text{radius}^2})

Visualizing the Link

  • \text{Diagonal Pairs:}
  • Li \leftrightarrow Mg
  • Be \leftrightarrow Al
  • B \leftrightarrow Si

Final Answer

  • \text{Elements } A \text{ and } B \text{ are } Li \text{ and } Mg.
  • \text{Correct Option: (d)}

The Sigma Insight: Alkali Metals

Solution Diagram

Decoding the Chemical Clues

Imagine you are a chemical detective, and the problem has just handed you two crucial pieces of evidence about two mystery elements, and .
First, they refuse to form solid hydrogencarbonates (also known as bicarbonates). Second, they have a special affinity for nitrogen, reacting directly with gas to form solid nitrides.
To crack this case, we need to scan the periodic table and see which groups exhibit these specific behaviors.

The Group 2 Suspects

Let's start by interrogating the Group 2 elements, the alkaline earth metals like Magnesium () and Calcium ().
These metals are known to be quite reactive with nitrogen upon heating. The reaction proceeds as follows:
Furthermore, the bicarbonates of Group 2 metals are notoriously unstable in the solid state. If you try to evaporate the water from an aqueous solution of , it decomposes into magnesium carbonate, water, and carbon dioxide. They only exist happily in an aqueous solution:
So, it is highly probable that one of our mystery elements belongs to Group 2.

The Group 1 Rebel

Now, let's look at Group 1, the alkali metals. Generally, metals like Sodium () and Potassium () do not react directly with nitrogen gas.
Additionally, they form very stable solid bicarbonates. Think of baking soda, which is solid . Based on this, Group 1 metals should be ruled out.
But wait! There is a famous rebel in Group 1: Lithium ().
Because Lithium is exceptionally small, its cation has a very high charge density and polarizing power. This allows it to form a stable lattice with the highly charged nitride ion ():
Similarly, this high polarizing power distorts the large bicarbonate ion () so severely that solid cannot exist; it decomposes upon attempted isolation. Lithium perfectly matches our clues!

The Diagonal Relationship

Why does Lithium, a Group 1 metal, behave so much like Magnesium, a Group 2 metal?
This is a beautiful manifestation of the diagonal relationship in the periodic table. As you move across a period from left to right, atomic size decreases and nuclear charge increases. As you move down a group, atomic size increases.
When you move diagonally (one step right and one step down), these two opposing effects roughly cancel each other out. This results in elements with very similar ionic potentials (charge-to-size ratios).
Because and have similar polarizing power, they exhibit strikingly similar chemical properties. They both form nitrides, and neither forms a solid bicarbonate.
Therefore, our mystery elements and are Lithium () and Magnesium ().

Similar Questions

JEE Main 2019
LEVELJEE Main

The metal that forms nitride by reacting directly with of air, is

(A)
(B)
(C)
(D)
JEE Main 2017
LEVELJEE Main

Both lithium and magnesium display several similar properties due to the diagonal relationship; however, the one which is incorrect is

(A)
Both form basic carbonates
(B)
Both form soluble bicarbonates
(C)
Both form nitrides
(D)
nitrates of both Li and Mg yield and on heating
JEE Main 2019
LEVELJEE Main

A metal on combustion in excess air forms X. X upon hydrolysis with water yields and along with another product. The metal is

(A)
Li
(B)
Mg
(C)
Rb
(D)
Na
JEE Main 2021
LEVELJEE Main

Match List I with List II. \begin{array}{ll} \text{List-I (Elements)} & \text{List-II (Properties)} \\ \text{A. Ba} & \text{(i) Organic solvent soluble compounds} \\ \text{B. Ca} & \text{(ii) Outer electronic configuration } 6s^2 \\ \text{C. Li} & \text{(iii) Oxalate insoluble in water} \\ \text{D. Na} & \text{(iv) Formation of very strong monoacidic base} \end{array} Choose the correct answer from the options given below

(A)
A-(ii), B-(iii), C-(i), D-(iv)
(B)
A-(iv), B-(i), C-(ii), D-(iii)
(C)
A-(iii), B-(ii), C-(iv), D-(i)
(D)
A-(i), B-(iv), C-(ii), D-(iii)
JEE Main 2021
LEVELJEE Main

Match List I with List II. Choose the correct answer from the options given below.

List-I

(P)
(Q)
(R)
(S)

List-II

(1)
Poor water solubility of salt
(2)
Most abundant element in cell fluid
(3)
Bicarbonate salt used in fire extinguisher
(4)
Carbonate salt decomposes easily on heating
JEE Main 2020
LEVELJEE Main

Among the statements (A)-(D), the correct ones are (A) lithium has the highest hydration enthalpy among alkali metals. (B) lithium chloride is insoluble in pyridine. (C) lithium cannot form ethynide upon its reaction with ethyne. (D) Both lithium and magnesium react slowly with .

(A)
(A) and (D) only
(B)
(B) and (C) only
(C)
(A), (C) and (D) only
(D)
(A), (B) and (D) only
JEE Main 2021
LEVELJEE Main

Find , and in the following reactions:

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

A hydrated solid on heating initially gives a monohydrated compound . upon heating above leads to an anhydrous white powder . and , respectively, are

(A)
baking soda and soda ash
(B)
washing soda and soda ash
(C)
baking soda and dead burnt plaster
(D)
washing soda and dead burnt plaster
JEE Main 2021
LEVELJEE Main

A s-block element (M) reacts with oxygen to form an oxide of the formula . The oxide is pale yellow in colour and paramagnetic. The element (M) is

(A)
Mg
(B)
Na
(C)
Ca
(D)
K
JEE Main 2020
LEVELJEE Main

Reaction of an inorganic sulphite X with dilute generates compound Y. Reaction of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound Z. Y and Z respectively, are

(A)
and
(B)
and
(C)
and
(D)
S and