Sigma Percentile
JEE Main 2019
LEVELJEE Main

Animated Solution for Chemistry - s-Block Elements: A hydrated solid on heating initially gives a monohydrated compound . upon heating above leads to an anhydrous white powder . and , respectively, are

Select Answer:

Visualized Solution

  • Baking soda is .
  • It does not contain any water of crystallization, so it is not a hydrated solid.
  • Therefore, options (a) and (c) are incorrect.

  • Gypsum is .
  • On heating, it forms Plaster of Paris , which is a hemihydrate, not a monohydrate.
  • Further heating gives dead burnt plaster .

  • Washing soda is sodium carbonate decahydrate: .

  • Compound is Sodium carbonate monohydrate.

  • Compound is anhydrous Sodium carbonate, known as Soda Ash.

  • Initial compound is Washing Soda.
  • Final compound is Soda Ash.

The Sigma Insight: Alkali Metals

Solution Diagram

The Thermal Journey of Hydrated Salts

Have you ever wondered what happens when you heat a crystal that looks perfectly dry, yet contains water hidden within its structure? This hidden water is known as the water of crystallization, and the way a salt loses this water upon heating can tell us exactly what that salt is. Let's embark on a chemical detective journey to identify the mysterious compounds , , and .

Analyzing the Suspects

Our first clue is that compound is a hydrated solid. Let's look at our options. Baking soda is sodium bicarbonate (). Does it have water of crystallization? No, it doesn't. It's an anhydrous powder in its natural state. So, we can immediately cross out any option suggesting is baking soda.
What about dead burnt plaster? This is anhydrous calcium sulphate (), which is formed by strongly heating gypsum (). However, when gypsum is heated, it first forms Plaster of Paris (), which is a hemihydrate, not a monohydrate. Since our mystery compound forms a monohydrate , gypsum doesn't fit the profile.

The Case for Washing Soda

This leaves us with washing soda. The chemical formula for washing soda is sodium carbonate decahydrate, written as . It's a highly hydrated solid, making it a perfect candidate for compound . Let's see how it behaves when the heat is turned up.
When washing soda is gently heated to a temperature below (which is ), it doesn't lose all its water at once. Instead, it undergoes a partial dehydration, losing exactly nine water molecules:
The resulting compound, , is sodium carbonate monohydrate. This perfectly matches the description of our intermediate compound !

The Final Transformation

Now, what happens if we crank up the heat? If we heat this monohydrate above , the thermal energy becomes sufficient to break the bond holding the final water molecule.
The water evaporates away, leaving behind a completely dry, white powder of anhydrous sodium carbonate (). In the chemical industry, this anhydrous form is famously known as soda ash. This is our final product, .
By carefully tracing the thermal decomposition steps, we've successfully identified that the initial hydrated solid is washing soda, and the final anhydrous powder is soda ash.

Similar Questions

JEE Main 2020
LEVELJEE Main

Reaction of an inorganic sulphite X with dilute generates compound Y. Reaction of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound Z. Y and Z respectively, are

(A)
and
(B)
and
(C)
and
(D)
S and
JEE Main 2019
LEVELJEE Main

A metal on combustion in excess air forms X. X upon hydrolysis with water yields and along with another product. The metal is

(A)
Li
(B)
Mg
(C)
Rb
(D)
Na
JEE Main 2011
LEVELJEE Main

The products obtained on heating will be

(A)
(B)
(C)
(D)
JEE Main 2020
LEVELJEE Main

On combustion of Li, Na and K in excess of air, the major oxides formed, respectively, are

(A)
, and
(B)
, and
(C)
, and
(D)
, and
JEE Main 2016
LEVELJEE Main

The main oxides formed on combustion of Li, Na and K in excess of air respectively are

(A)
, and
(B)
, and
(C)
, and
(D)
, and
JEE Main 2021
LEVELJEE Main

Match List-I with List-II. Choose the correct answer form the options given below.

(A)
A-(iv), B-(iii), C-(i), D-(ii)
(B)
A-(i), B-(iii), C-(iv), D-(ii)
(C)
A-(iv), B-(i), C-(ii), D-(iii)
(D)
A-(iii), B-(ii), C-(i), D-(iv)
JEE Main 2021
LEVELJEE Main

One of the by-products formed during the recovery of from solvay process is

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

A s-block element (M) reacts with oxygen to form an oxide of the formula . The oxide is pale yellow in colour and paramagnetic. The element (M) is

(A)
Mg
(B)
Na
(C)
Ca
(D)
K
JEE Main 2021
LEVELJEE Main

Match List-I with List-II. Choose the most appropriate answer from the options given below.

(A)
A II, B II, C III, D II, E III
(B)
A II, B III, C II, D I, E III
(C)
A II, B II, C III, D I, E III
(D)
A II, B I, C II, D III, E III
JEE Main 2020
LEVELJEE Main

Two elements and have similar chemical properties. They don't form solid hydrogencarbonates, but react with nitrogen to form nitrides. and , respectively, are

(A)
Na and Rb
(B)
Na and Ca
(C)
Cs and Ba
(D)
Li and Mg