Sigma Percentile
JEE Main 2021
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Animated Solution for Chemistry - Organic Chemistry: The transformation occurring in Duma's method is given below The value of is ......... . (Integer answer)

Enter Numerical Value:

Visualized Solution

\text{Duma's Method Equation}

\text{Principle of Atom Conservation}

\text{Hydrogen Atoms in Reactants}

\text{Hydrogen Atoms in Products}

\text{Equating Hydrogen Atoms}

The Sigma Insight: Nomenclature and Characterisation

Solution Diagram

Decoding Duma's Method

Duma's method is a classic technique used for the quantitative estimation of nitrogen in organic compounds. In this process, a known mass of the organic compound is heated with excess copper(II) oxide () in an atmosphere of carbon dioxide.
The carbon and hydrogen in the compound are oxidized to carbon dioxide and water, respectively, while the nitrogen is released as free nitrogen gas.

The Principle of Atom Conservation

To solve this problem, we don't need to memorize complex formulas. We just need to rely on a fundamental law of chemistry: the Principle of Atom Conservation (POAC).
This principle states that atoms can neither be created nor destroyed in a chemical reaction. Therefore, the total number of atoms of a specific element on the reactant side must perfectly match the total number of atoms of that same element on the product side.

Balancing the Hydrogen Atoms

Let's apply this principle specifically to the hydrogen atoms in our given equation:
First, we examine the reactant side. The only molecule containing hydrogen is our starting organic compound, . By simply looking at its chemical formula, we can see that it contains exactly 7 hydrogen atoms.
Next, we shift our focus to the product side. All the hydrogen from the organic compound has been converted into water (). The stoichiometric coefficient for water in the balanced equation is given as .
Since each water molecule contains 2 hydrogen atoms, the total number of hydrogen atoms on the product side is:

The Final Calculation

Now, we equate the number of hydrogen atoms from both sides of the reaction:
And there we have it! The value of is simply 7. This problem beautifully demonstrates how a seemingly complex organic chemistry equation can be solved with basic stoichiometry and atom conservation.

Similar Questions

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In Duma's method of estimation of nitrogen, of an organic compound gave of nitrogen collected at and of Hg pressure. The percentage composition of nitrogen in the compound is ......... . (Round off to the nearest integer). [Given: Aqueous tension at of Hg]

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An organic compound is estimated through Dumas method and was found to evolved 6 moles of , 4 moles of and 1 mole of nitrogen gas. The formula of the compound is

(A)
(B)
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Comprehension Passage

Consider the following reaction sequence in which J, K, L and M are the major products. Given: Atomic mass (in amu): H : 1, C : 12, N : 14, O : 16, S : 32, Br : 80, Ba : 137
Question 1:

The volume of 1 M aqueous required to completely neutralize the ammonia evolved from 5.72 g of L in Kjeldahl's method of nitrogen estimation is ____ mL.

Question 2:

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The correct match between item 'I' and item 'II' is \begin{array}{clcl} \hline & \textbf{Item 'I'} & & \textbf{Item 'II'} \\ & \text{(Compound)} & & \text{(Reagent)} \\ \hline \text{(A)} & \text{Lysine} & \text{(P)} & \text{1-naphthol} \\ \text{(B)} & \text{Furfural} & \text{(Q)} & \text{Ninhydrin} \\ \text{(C)} & \text{Benzyl alcohol} & \text{(R)} & \text{KMnO}_4 \\ \text{(D)} & \text{Styrene} & \text{(S)} & \text{Ceric ammonium nitrate} \\ \hline \end{array}

(A)
(A) Q, (B) R, (C) S, (D) P
(B)
(A) R, (B) P, (C) Q, (D) S
(C)
(A) Q, (B) P, (C) S, (D) R
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Match the following :

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(I)-(B), (II)-(D), (III)-(E), (IV)-(A)
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The correct match between items I and II is

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(C)
(A) (S); (B) (R); (C) (P)
(D)
(A) (R); (B) (P); (C) (S)
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