Sigma Percentile
JEE Main 2021 (25 July Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Matrices and Determinants: The values of and , for which the system of equations , , has no solution, are:

Select Answer:

Visualized Solution

Identify the System of Equations

  • Given system of equations:

Cramer's Rule Condition for No Solution

  • For a system to have no solution:
  • 1.
  • 2. At least one of

Setup the Main Determinant

  • Coefficient determinant :

Expand along the First Row

  • Expanding along :

Simplify the Expression for

Set to find

  • For no solution, :

Setup for the Second Condition

  • Replacing the third column with constants:

Expand

  • Expanding along :

Simplify the Expression for

Apply the Non-Zero Condition

  • For no solution, :

Final Conclusion

  • The required values are:
  • This matches option (1).

The Sigma Insight: Solution of System of Linear Equations (Matrix Method and Cramer's Rule)

Solution Diagram

Analyzing the Setup

Imagine you are standing in a three-dimensional space with three planes defined by the following linear equations:
In linear algebra, these equations represent physical surfaces. While these planes typically intersect at a single point, we are investigating the condition for no solution, where the planes never meet at a common point.

The Cramer's Rule Master Key

To unlock this mystery, we utilize the machinery of Cramer's Rule. We define the main determinant of the coefficient matrix, , as:
For a system to have no solution, the first requirement is that the system must be singular, meaning . If $\Delta eq 0$, the system would possess a unique solution.
However, is a necessary but not sufficient condition. We must also ensure the system is not 'dependent' (which would lead to infinite solutions) by verifying that at least one of the numerator determinants—, , or —is non-zero.

The Calculation

Unveiling 'a'
Let us expand along the first row:
Performing the algebraic expansion:
Combining the terms, we find:
Setting this to zero, we immediately see that . This is the value that renders our system singular.

The Twist

The Condition for 'b'
To ensure the system is truly inconsistent, we construct by replacing the third column of the coefficient matrix with the constants from the right side of our equations:
Expanding this along the first row:
Simplifying this expression:
This collapses into:
For the system to have no solution, we must satisfy the condition $\Delta_z eq 0$. Therefore, $b eq 13$.

The Final Synthesis

By setting , we forced the system to be singular, yielding . By ensuring $\Delta_z eq 0$, we guaranteed that the system is inconsistent rather than dependent, yielding $b eq 13$.
The values for which the system has no solution are and $b eq 13$. This result describes a configuration where the planes exist in space while forever avoiding a common intersection.

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