Analyzing the Setup
Welcome, future IITians! Today, we are not just solving a probability problem; we are dissecting the very nature of truth and falsehood. We are given the probabilities of two witnesses, A and B, telling the truth:
We need to find the probability that they contradict each other.
Visualizing the Sample Space
Let us visualize this using a grid. Imagine a rectangle with a width of 5 units and a height of 4 units, where the total area is 20 square units. This grid represents every possible outcome of their testimony.
The horizontal axis represents A, and the vertical axis represents B. Because A speaks the truth 4 out of 5 times, we shade 4 columns for truth and 1 for a lie. Similarly, for B, we shade 3 rows for truth and 1 for a lie.
Defining the Contradiction
What does it mean to contradict? It means they are not in sync. If A is honest, B must be deceitful. If A is deceitful, B must be honest.
Mathematically, we are looking for two mutually exclusive events:
1. Case 1: A is true AND B is false, denoted as A∩Bˉ.
2. Case 2: A is false AND B is true, denoted as Aˉ∩B.
Because these events are independent, the probability of the intersection is the product of the individual probabilities.
The Master Equation
For Case 1, we calculate:
P(A)⋅P(Bˉ)=54⋅(1−43)=54⋅41=204
For Case 2, we calculate:
P(Aˉ)⋅P(B)=(1−54)⋅43=51⋅43=203
Final Calculation
Since these two cases are mutually exclusive, we sum them up to find the total probability of contradiction:
P(Contradiction)=204+203=207
The final probability of the witnesses contradicting each other is 207.
Remember, in JEE Advanced, the key is not just the calculation, but the visualization. Whether you use the grid method or the algebraic method, always ensure you understand the 'why' behind the 'what'.