Analyzing the Setup
The binomial theorem states that any term in the expansion of (a+b)n is given by the general term formula:
In this problem, we are given the expression (41/4+51/6)120. Here, a=41/4, b=51/6, and n=120.
The Prime Base Reduction
A common trap in JEE problems is failing to reduce bases to their prime forms. We must express 4 as 22:
Substituting this into our general term formula, we get:
Tr+1=120Cr(21/2)120−r(51/6)r
Simplifying the exponents, the expression becomes:
Tr+1=120Cr⋅22120−r⋅56r
Establishing Rationality Conditions
For the term Tr+1 to be rational, the exponents of the prime bases 2 and 5 must be integers. This yields two simultaneous conditions:
1. 2120−r∈Z⟹r must be even.
2. 6r∈Z⟹r must be a multiple of 6.
Since any multiple of 6 is inherently an even number, the condition simplifies to r being a multiple of 6. Given that 0≤r≤120, the possible values for r are 0,6,12,…,120.
Final Calculation
The values of r form an arithmetic progression where the first term a=0, the common difference d=6, and the last term l=120. The number of terms N is calculated as:
The total number of rational terms in the expansion is 21.