Analyzing the Setup
Imagine you are standing before the expression (341+581)60. It looks daunting, but in the world of JEE Advanced, we use the elegance of the Binomial Theorem rather than brute force.
Our mission is to find n, the number of irrational terms, and then solve a final divisibility puzzle.
The DNA of the Expansion
Every term in a binomial expansion follows the general term formula:
Tr+1=nCran−rbr
Here, our
a=341, our
b=581, and our
n=60. Plugging these into the formula, we get:
Tr+1=60Cr(341)60−r(581)r
Using the laws of indices, we simplify this to:
Tr+1=60Cr⋅3460−r⋅58r
The Rationality Filter
A term is rational if and only if its exponents are integers. If the exponents are fractions, the term involves roots, making it irrational.
We require both 460−r∈Z and 8r∈Z.
Starting with the second condition,
8r∈Z implies that
r must be a multiple of
8. Given the constraint
0≤r≤60, our candidates for
r are:
{0,8,16,24,32,40,48,56}
Now, we check the first condition: 460−r∈Z. Since 60 is divisible by 4, we simply need r to be divisible by 4.
Because all our candidates are multiples of 8, they are automatically multiples of 4. Thus, all 8 values of r produce rational terms.
The Final Count
The total number of terms in the expansion is n+1=60+1=61.
Since there are
8 rational terms, the number of irrational terms
n is:
n=61−8=53
The question asks for the value of
(n−1). Therefore:
n−1=53−1=52
The final result is 52.