Analyzing the Setup
My dear student, welcome to the fascinating world of the Binomial Distribution. Today, we are not just solving a problem; we are peeling back the layers of a mathematical structure that governs everything from coin flips to quality control in manufacturing.
We are given two vital clues: the mean μ=4 and the variance σ2=2. These are the heartbeat of our distribution.
Decoding the Parameters
Imagine you are standing before a mystery box. We know the mean is np=4 and the variance is npq=2.
The beauty of mathematics lies in its elegance. If we look at the ratio of the variance to the mean, something magical happens:
The n and p terms, which seem so elusive, simply vanish. This leaves us with:
Just like that, the probability of failure is revealed to be 0.5.
The Symmetry of Success
Now that we have q, the probability of success p is just a heartbeat away. Because success and failure are complementary, we know that p+q=1.
With q=21, it follows that:
We have discovered that in this specific experiment, success and failure are perfectly balanced, like a fair coin toss.
Now, let us find the total number of trials n. Returning to our mean equation, np=4, we substitute our value for p:
Multiplying both sides by 2, we find n=8. We have successfully mapped the entire landscape of our distribution: n=8, p=0.5, and q=0.5.
The Final Calculation
The question asks for the probability that X=1. We turn to the Binomial Probability Mass Function:
Substituting our values, we get:
P(X=1)=(18)(21)1(21)8−1
Simplifying this, (18) is simply 8. The probability terms combine to (21)8. Thus:
When we divide 8 by 256, we arrive at our final, elegant answer:
You see? By breaking the problem down into these logical steps, we didn't just find the answer; we understood the structure of the distribution itself. Keep this clarity with you as you tackle more complex problems. You are doing fantastic.