Sigma Percentile
JEE Main 2023 (24 January Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Functions: The equation , where denotes the greatest integer function, has:

Select Answer:

Visualized Solution

The Given Equation

  • Given equation:
  • Goal: Find the number of real solutions for .
  • Key concept: Greatest Integer Function .

Rearranging Terms

  • Group standard polynomial terms on the Left Hand Side (LHS).
  • Group terms containing on the Right Hand Side (RHS).

Factorizing the LHS

  • LHS:
  • Splitting the middle term:
  • Factored form:

Factorizing the RHS

  • RHS:
  • Take common:

Equating the Factors

  • Equating both sides:
  • Bring all terms to one side:

Factoring out

  • Factor out :
  • The product of two factors is zero.

Case 1:

  • Setting the first factor to zero:
  • Solution:
  • At , both functions intersect at .

Case 2:

  • Setting the second factor to zero:
  • Rearranging to isolate constants:

Fractional Part Function

  • Recall the definition:
  • Our equation becomes:

Range of Fractional Part

  • Fundamental property:
  • But our result requires
  • Conclusion: No real value of satisfies this condition.

Final Conclusion

  • Case 1 gave .
  • Case 2 gave no solution.
  • The equation has a unique solution in .

The Sigma Insight: Classification of Functions

Solution Diagram

Analyzing the Setup

We are tasked with solving the equation:
At first glance, this appears to be a complex mix of polynomials and step functions. However, in the context of JEE Advanced, we can resolve this by systematically separating the algebraic terms from the greatest integer function.

The Strategy of Separation

To begin, we rearrange the equation to isolate the terms involving on one side:
By moving the term to the right, we create a structure that is ready for factorization. On the left, we have a standard quadratic expression, and on the right, we have a common factor of .

The Trap of Simplification

Factoring both sides, we obtain:
A common mistake is to divide both sides by . This is a mathematical error because it assumes $x eq 1$ and risks losing a valid solution. Instead, we bring all terms to one side:
Factoring out the common term , we arrive at:
This product equals zero if and only if at least one of the factors is zero.

The Fractional Part Revelation

Case 1: This immediately yields the solution .
Case 2: Rearranging this gives:
Recall that the expression is the definition of the fractional part of , denoted as . By definition, the fractional part function is bounded such that .
Since the value falls outside the interval , it is impossible for to equal . Therefore, Case 2 yields no real solutions.

The Final Verdict

We have navigated the logic and avoided the common pitfalls of division. Case 1 provided the solution , while Case 2 provided no solutions.
Thus, the equation has a unique solution in the set of real numbers:

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