Analyzing the Setup
We are tasked with solving the equation:
x2−4x+[x]+3=x[x]
At first glance, this appears to be a complex mix of polynomials and step functions. However, in the context of JEE Advanced, we can resolve this by systematically separating the algebraic terms from the greatest integer function.
The Strategy of Separation
To begin, we rearrange the equation to isolate the terms involving
[x] on one side:
x2−4x+3=x[x]−[x]
By moving the [x] term to the right, we create a structure that is ready for factorization. On the left, we have a standard quadratic expression, and on the right, we have a common factor of [x].
The Trap of Simplification
Factoring both sides, we obtain:
(x−1)(x−3)=[x](x−1)
A common mistake is to divide both sides by
(x−1). This is a mathematical error because it assumes
$x
eq 1$ and risks losing a valid solution. Instead, we bring all terms to one side:
(x−1)(x−3)−[x](x−1)=0
Factoring out the common term
(x−1), we arrive at:
(x−1)(x−3−[x])=0
This product equals zero if and only if at least one of the factors is zero.
The Fractional Part Revelation
Case 1: x−1=0
This immediately yields the solution x=1.
Case 2: x−3−[x]=0
Rearranging this gives:
x−[x]=3
Recall that the expression x−[x] is the definition of the fractional part of x, denoted as {x}. By definition, the fractional part function is bounded such that 0≤{x}<1.
Since the value 3 falls outside the interval [0,1), it is impossible for {x} to equal 3. Therefore, Case 2 yields no real solutions.
The Final Verdict
We have navigated the logic and avoided the common pitfalls of division. Case 1 provided the solution x=1, while Case 2 provided no solutions.
Thus, the equation has a unique solution in the set of real numbers:
x=1