Sigma Percentile
JEE Main 2026 (22 January Shift 2)
LEVELJEE Main

Animated Solution for Mathematics - Functions: Let , where is the greatest integer function. Then

Select Answer:

Visualized Solution

Analyzing the Function

  • Given:
  • The function involves the Greatest Integer Function (GIF), denoted by .
  • Our goal is to analyze the behavior of to check the given options.

Property of Greatest Integer Function

  • Recall a fundamental property of GIF:
  • , where
  • Here, is an integer, so we can apply this property to .

Applying the Property

  • Substitute into the original function.
  • Notice the parentheses to avoid sign errors.

Simplifying the Expression

  • Expand the negative sign:
  • Combine the constant terms:

Substitution for Clarity

  • To make the algebra easier, let's introduce a dummy variable.
  • Let , where is an integer ().
  • The function becomes a simple quadratic in terms of :

Factorizing the Quadratic

  • We need to factorize .
  • Find two numbers that multiply to and add to .
  • The numbers are and .

Testing Option 2:

  • Let's check the condition where the function is strictly negative.
  • Set .
  • This means .

Solving the Inequality for

  • Solve using the wavy curve method.
  • The critical points are and .
  • The inequality holds between the roots:

Identifying Integer Values of

  • We found .
  • But remember our initial substitution: , so MUST be an integer.
  • The integers strictly between and are:

Mapping back to

  • Now, we map each integer value of back to the corresponding interval for .
  • If
  • If
  • If
  • If

Combining the Intervals

  • To find the complete range of where , we take the union of these intervals.
  • Notice how the intervals connect perfectly.
  • Final combined interval:

Final Conclusion

  • We have proven that exactly when .
  • This perfectly matches Option 2.
  • For , .
  • Therefore, Option 2 is the correct answer.

The Sigma Insight: Classification of Functions

Solution Diagram

Analyzing the Setup

We are presented with the function . The presence of the greatest integer function, denoted by the square brackets , requires us to utilize its fundamental properties to simplify the expression.
We rely on the identity: for any integer , . In our case, , which is clearly an integer. Thus, we can rewrite as .

Simplifying the Expression

Substituting this into our original function, we obtain:
Expanding the expression carefully to avoid sign errors, we get:
To make this more intuitive, let us introduce a dummy variable . Since the output of the greatest integer function is always an integer, must be an integer. Our function now takes the familiar quadratic form:

Solving the Inequality

We can factorize this quadratic expression as:
We are looking for the region where , which implies:
Using the wavy curve method, we identify the critical points at and . The inequality holds for the interval:
Since must be an integer, the possible values for are .

Final Mapping and Result

Now, we must map these values back to the domain of . For each integer , the condition corresponds to the interval .
Applying this to our set of integers, we obtain the following intervals: , , , and .
Taking the union of these intervals, we find the final solution:
This is the region where our function is negative. By simplifying the expression, transforming it into a standard quadratic, and mapping the discrete integer results back to the continuous domain, we have successfully conquered the staircase.

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