Sigma Percentile
JEE Advanced 2008
LEVELJEE Main

Animated Solution for Mathematics - Sequence and Series: Suppose four distinct positive numbers are in G.P. Let and . STATEMENT - 1 : The numbers are neither in A.P. nor in G.P. and STATEMENT - 2 : The numbers are in H.P.

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Visualized Solution

Visualizing the Sequences and

  • Let the G.P. terms be .
  • We construct the sequence by progressively adding these terms.
  • To visualize, let's take a concrete example: and common ratio .
  • This gives .
  • The cumulative sums are .

General Representation of G.P. Terms

  • Let the first term of the G.P. be and the common ratio be .
  • The terms are written as:
  • Since the terms are distinct and positive: .

Expressing in terms of and

  • Using the definitions of :

Testing the A.P. Condition

  • For to be in A.P., the common difference must be constant:

Evaluating the Differences

  • Calculate the differences:
  • Since and , we have .
  • Therefore, the sequence is not in A.P.

Testing the G.P. Condition

  • For to be in G.P., the common ratio must be constant:

Analyzing the G.P. Ratios

  • Substitute the expressions:
  • Equating them:

Solving for in the G.P. Equation

  • Expand the equation:
  • Subtract from both sides:
  • Since , is impossible.
  • Therefore, the sequence is not in G.P.

Testing the H.P. Condition

  • For to be in H.P., their reciprocals must be in A.P.:

Algebraic Simplification of the H.P. Equation

  • Substitute the expressions:
  • Cancel from both sides:
  • Combine the RHS:

Cross-Multiplying and Expanding

  • Cross-multiply:
  • Expand both sides:
  • LHS:
  • RHS:

Finding the Roots for

  • Equate LHS and RHS:
  • Subtract from both sides:
  • Since , . No real positive solution exists!
  • Therefore, the sequence is not in H.P.

Verifying Statement 1 and Statement 2

  • Statement 1: are neither in A.P. nor in G.P. (True)
  • Statement 2: are in H.P. (False)
  • Hence, Statement 1 is True, and Statement 2 is False.

The Sigma Insight: Geometric Progression (G.P.)

Solution Diagram

Analyzing the Setup

We are given a geometric progression (G.P.) with distinct positive terms: . Let the first term be and the common ratio be .
Given the constraints that terms are distinct and positive, we have , , and $r eq 1$. The terms are defined as: , , , and .
We construct a new sequence using the partial sums of this G.P.:

The Arithmetic Progression Test

For a sequence to be in Arithmetic Progression (A.P.), the difference between consecutive terms must be constant. We check if .
Calculating the differences:
For the sequence to be in A.P., we require . Since and $r eq 1$, we divide by to obtain .
This contradicts our initial constraint that $r eq 1$. Therefore, the sequence is definitively not in A.P.

The Geometric Progression Test

For a sequence to be in Geometric Progression (G.P.), the ratio of consecutive terms must be constant. We check if .
Substituting our expressions:
Equating these ratios:
Cross-multiplying yields . Expanding the left side gives .
Subtracting from both sides results in . Since our terms are positive, must be greater than zero, meaning the sequence is not in G.P.

The Harmonic Progression Test

For to be in Harmonic Progression (H.P.), their reciprocals must be in A.P., satisfying the condition:
Substituting our expressions and canceling :
Combining the right side:
Cross-multiplying gives:
Simplifying the equation leads to , or . Since , this equation has no real solution.
Thus, the sequence is not in H.P. We have systematically proven that the sequence does not follow the standard progression rules of A.P., G.P., or H.P.

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