Animated Solution for Chemistry - Hydrocarbons: Which of the following reagent is used for the following reaction ?
CH3CH2CH3⟶CH3CH2CHO
Select Answer:
Visualized Solution
Identifying the Transformation
Reactant: CH3CH2CH3 (Propane, an alkane)
Product: CH3CH2CHO (Propanal, an aldehyde)
The Challenge of Alkane Oxidation
Alkanes resist oxidation under normal conditions.
Controlled oxidation requires specific catalysts to stop at the aldehyde stage without over-oxidizing to a carboxylic acid.
Evaluating the Catalysts
Cu/523 K/100 atm→Alcohols
Mo2O3/Δ→Aldehydes
(CH3COO)2Mn/Δ→Carboxylic acids
The Chemical Equation
CH3CH2CH3Mo2O3,ΔCH3CH2CHO+H2O
Final Conclusion
Correct Option: (b) Molybdenum oxide
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The Sigma Insight: Hydrocarbons
Solution Diagram
The Inert Nature of Alkanes
Alkanes are notoriously unreactive under normal laboratory conditions. Their strong, non-polar C−C and C−H bonds make them resistant to attack by common acids, bases, and oxidizing agents. However, this doesn't mean they are completely invincible. Under drastic conditions—such as high temperatures, high pressures, and in the presence of specific catalysts—alkanes can undergo a fascinating process known as controlled oxidation.
The Challenge of Controlled Oxidation
When you burn an alkane in the presence of excess oxygen, it undergoes complete oxidation (combustion) to yield carbon dioxide and water.
But what if we want to stop halfway? What if we want an alcohol, an aldehyde, or a carboxylic acid? This is where the magic of specific catalysts comes into play. The choice of catalyst acts like a brake, stopping the oxidation process at the exact functional group we desire.
The Catalyst Arsenal
Let's break down the specific reagents used for different stages of alkane oxidation:
1. Copper (Cu) at High Temperature and Pressure:
When a mixture of an alkane and oxygen is passed through a copper tube at 523 K and 100 atm, the oxidation stops at the alcohol stage.
2CH4+O2Cu/523 K/100 atm2CH3OH
2. Molybdenum Oxide (Mo2O3):
If we want to synthesize an aldehyde, we use Molybdenum oxide upon heating. This catalyst is perfectly tuned to halt the oxidation right after the aldehyde is formed, preventing it from turning into an acid.
CH4+O2Mo2O3/ΔHCHO+H2O
In our specific problem, propane is converted to propanal:
CH3CH2CH3+O2Mo2O3/ΔCH3CH2CHO+H2O
3. Manganese Acetate (CH3COO)2Mn:
To push the oxidation one step further to a carboxylic acid, we employ Manganese acetate.
2CH3CH3+3O2(CH3COO)2Mn/Δ2CH3COOH+2H2O
Conclusion
Memorizing these specific catalysts is a high-yield strategy for JEE. While the question directly asked for the reagent to form an aldehyde (Molybdenum oxide), understanding the entire spectrum of controlled oxidation empowers you to tackle any variation of this concept.