Sigma Percentile
JEE Main 2015
LEVELBoard

Animated Solution for Physics - Dual Nature of Matter and Radiation: Match List I (fundamental experiment) with List II (its conclusion) and select the correct option from the choices given below the list.

Select Answer:

Visualized Solution

  • We need to match three fundamental experiments with their corresponding conclusions.

  • Electrons colliding with mercury atoms lose energy only in specific, quantized amounts.

  • Light behaves as packets of energy called photons, which knock out electrons from a metal surface.

  • Electrons scattered by a nickel crystal produce a diffraction pattern, confirming de Broglie's hypothesis.

The Sigma Insight: Matter Waves and de Broglie Relation

The Dawn of Quantum Mechanics

Imagine the early 20th century. Classical physics, which had beautifully explained the macroscopic world for centuries, was suddenly struggling to make sense of the microscopic realm. The universe was not as continuous and predictable as Newton and Maxwell had thought. It was chunky, probabilistic, and deeply weird.
To understand this transition, we look at three monumental experiments that acted as the pillars of modern quantum mechanics. Let's decode them one by one.

The Franck-Hertz Experiment

Staircases of Energy
In 1914, James Franck and Gustav Hertz set out to probe the internal structure of the atom. They designed an elegant experiment where they fired electrons through a vacuum tube filled with mercury vapor.
According to classical physics, an electron should be able to transfer any arbitrary amount of its kinetic energy to a mercury atom during a collision. But that's not what happened. Franck and Hertz observed that the electrons would bounce off the mercury atoms elastically, losing almost no energy, until they reached a very specific kinetic energy threshold: exactly .
At exactly , the electrons suddenly lost all their energy. Why? Because the mercury atom could only absorb energy in specific, quantized chunks. This was the first direct experimental proof of Niels Bohr's radical idea: atoms possess discrete energy levels. The atom is like a staircase; you can stand on step 1 or step 2, but you cannot hover in between. Thus, the Franck-Hertz experiment perfectly matches with the conclusion of discrete energy levels of an atom.

The Photoelectric Effect

Light as Bullets
While atoms were revealing their discrete nature, light was also undergoing an identity crisis. For decades, light was universally accepted as a continuous electromagnetic wave. But the photoelectric effect threw a wrench into this theory.
When high-frequency light shines on a metal surface, it ejects electrons. Classical wave theory predicted that if you shine a very bright, low-frequency light (like intense red light) for a long enough time, the energy would eventually "build up" and knock an electron loose. But experiments showed that no matter how intense the red light was, or how long you waited, no electrons were ever ejected. However, even a very dim blue light would eject electrons instantaneously.
In 1905, Albert Einstein solved this mystery by proposing that light is not a continuous wave, but a stream of discrete energy packets, now called photons. The energy of each photon is given by $E = h u$. A single photon of blue light has enough energy to knock out an electron, while a photon of red light does not. This brilliant insight firmly established the particle nature of light.

The Davisson-Germer Experiment

Matter Rides the Wave
If light, which was thought to be a wave, could act like a particle, could a particle act like a wave? In 1924, Louis de Broglie made this bold hypothesis, suggesting that all matter has an associated wavelength given by .
Three years later, Clinton Davisson and Lester Germer accidentally proved him right. They were firing a beam of electrons at a piece of nickel. After a vacuum tube broke and they had to heat the nickel to clean it, the nickel formed large crystal domains. When they resumed firing electrons, they didn't see the electrons bouncing off randomly like billiard balls. Instead, they observed a distinct diffraction pattern.
Diffraction is a hallmark property of waves! The electrons were interfering with each other just like ripples in a pond. The spacing of the nickel atoms acted as a diffraction grating, and the observed diffraction peaks perfectly matched the wavelength predicted by de Broglie's formula. This groundbreaking experiment undeniably confirmed the wave nature of electrons.

Bringing It All Together

Matching the pieces of this quantum puzzle: - A. Franck-Hertz experiment 2. Discrete energy levels of atom - B. Photo-electric experiment 1. Particle nature of light - C. Davisson-Germer experiment 3. Wave nature of electron
This corresponds to the combination A-2, B-1, C-3, making option (c) the correct choice. These three experiments collectively shattered classical mechanics and built the foundation of the quantum world we study today.

Similar Questions

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This question has Statement I and Statement II. Of the four choices given the statements, choose the one that describes the two statements. Statement I Davisson-Germer experiment established the wave nature of electrons. Statement II If electrons have wave nature, they can interfere and show diffraction.

(A)
Statement I is false, Statement II is true
(B)
Statement I is true, Statement II is false
(C)
Statement I is true, Statement II is true; Statement I is the correct explanation of Statement I
(D)
Statement I is true, Statement II is true; Statement II is not the correct explanation of Statement I
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An electron of mass and a photon have same energy . The ratio of wavelength of electron to that of photon is ( being the velocity of light)

(A)
(B)
(C)
(D)
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Formation of covalent bonds in compounds exhibits

(A)
wave nature of electron
(B)
particle nature of electron
(C)
both wave and particle nature of electron
(D)
None of the above
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An electron (of mass ) and a photon have the same energy in the range of a few electron volt. The ratio of the de Broglie wavelength associated with the electron and the wavelength of the photon is ( speed of light in vacuum)

(A)
(B)
(C)
(D)
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The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is . Let be the de-Broglie wavelength of the proton and be the wavelength of the photon. The ratio is proportional to

(A)
(B)
(C)
(D)
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Comprehension Passage

Wave property of electrons implies that they will show diffraction effects. Davisson and Germer demonstrated this by diffracting electrons from crystals. The law governing the diffraction from a crystal is obtained by requiring that electron waves reflected from the planes of atoms in a crystal interfere constructively (see figure).
Question 1:

Electrons accelerated by potential are diffracted from a crystal. If and , should be about (, , )

(A)
2000 V
(B)
50 V
(C)
500 V
(D)
1000 V
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An electron, a doubly ionised helium ion () and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths , and is

(A)
(B)
(C)
(D)
JEE Advanced 2016
LEVELJEE Advanced

Light of wavelength falls on a cathode plate inside a vacuum tube as shown in the figure. The work function of the cathode surface is and the anode is a wire mesh of conducting material kept at a distance from the cathode. A potential difference is maintained between the electrodes. If the minimum de Broglie wavelength of the electrons passing through the anode is , which of the following statements(s) is (are) true?

* Multiple Correct Options
(A)
increases at the same rate as for
(B)
is approximately halved, if is doubled
(C)
decreases with increase in and
(D)
For large potential difference (), is approximately halved if is made four times.
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An electron (mass ) with initial velocity is in an electric field . If is initial de-Broglie wavelength of electron, then its de Broglie wavelength at time is given by

(A)
(B)
(C)
(D)
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Electrons with de-Broglie wavelength fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-rays is

(A)
(B)
(C)
(D)