Sigma Percentile
JEE Main 2003
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: Let and be two roots of the equation , being complex. Further, assume that the origin, and form an equilateral triangle. Then

Select Answer:

Visualized Solution

Visualizing the Triangle

  • Given: and are roots of .
  • Vertices of the triangle: , , and .
  • The triangle is equilateral.

Sum of Roots

  • From the equation :
  • Sum of roots:

Product of Roots

  • Product of roots:

The Equilateral Condition

  • Condition for an equilateral triangle with vertices :

Substituting the Origin

  • Since one vertex is the origin, let .
  • Substituting into the condition:

Simplified Equation

  • The condition simplifies to:

Completing the Square

  • Using the algebraic identity:
  • Rewrite the Left Hand Side:

Rearranging the Terms

  • Transposing to the Right Hand Side:

Final Substitution

  • Substitute and :

Conclusion & Takeaway

  • Simplifying the equation:
  • Key Takeaway: For roots of to form an equilateral triangle with the origin, the condition is .

The Sigma Insight: Geometrical Applications of Complex Numbers

Solution Diagram

Analyzing the Setup

Imagine you are standing on the complex plane, looking at the origin and two complex numbers and . These three points form a perfectly symmetric equilateral triangle.
This geometric constraint implies rotational symmetry. If you rotate about the origin by , you land on . This symmetry is the key to unlocking the relationship between the coefficients of the quadratic equation .

The Algebraic Bridge

Vieta's Formulas
We are given the quadratic equation . From the fundamental theorem of algebra, we know that the roots and are intimately connected to the coefficients and .
Specifically, the sum of the roots is given by:
The product of the roots is given by:
These two relations serve as our bridge between the abstract world of complex roots and the concrete world of coefficients.

The Equilateral Condition

A Powerful Tool
For any three complex numbers to form an equilateral triangle, they must satisfy the following condition:
In our specific case, one of the vertices is the origin, so we set . When we substitute into this condition, the terms , , and vanish.
We are left with the simplified constraint:

The Final Synthesis

We connect the geometric constraint with our algebraic relations using the identity:
Substituting this into our constraint, we obtain:
Rearranging the terms leads to:
Substituting the Vieta's relations , we arrive at the final condition:

A Moment of Celebration

We started with a geometric shape and, through the power of complex algebra, arrived at a clean, elegant condition. This is the beauty of mathematics, where the visual and the algebraic are woven into a single truth.
You have successfully navigated this classic JEE problem. Remember: every complex problem is just a simple truth waiting to be uncovered.

Similar Questions

JEE Advanced 1983
LEVELJEE Main

Prove that the complex numbers and the origin form an equilateral triangle only if .

JEE Advanced 1997
LEVELJEE Advanced

Let and be roots of the equation , where the coefficients and may be complex numbers. Let and represent and in the complex plane. If and , where is the origin, prove that .

JEE Advanced 1989
LEVELJEE Main

If , are the numbers between 0 and 1 such that the points and form an equilateral triangle, then and

JEE Main 2021 (18 March Shift 1)
LEVELJEE Main

Let be the roots of the equation and form an equilateral triangle with origin. Then, the value of is

JEE Advanced 1981
LEVELJEE Main

Let the complex number be the vertices of an equilateral triangle. Let be the circumcentre of the triangle. Then prove that .

JEE Main 2021 (18 March Shift 2)
LEVELJEE Main

Let a complex number be . Let another complex number be such that and . Then the area of the triangle with vertices origin, and is equal to:

(A)
4
(B)
(C)
(D)
2
JEE Advanced 2001S
LEVELJEE Main

The complex numbers and satisfying are the vertices of a triangle which is

(A)
of area zero
(B)
right-angled isosceles
(C)
equilateral
(D)
obtuse-angled isosceles
JEE Main 2011
LEVELJEE Main

Let be real and be a complex number. If has two distinct roots on the line , then it is necessary that

(A)
(B)
(C)
(D)
JEE Advanced 1994
LEVELJEE Main

Suppose are the vertices of an equilateral triangle inscribed in the circle . If then

JEE Main 2025 (January)
LEVELJEE Main

Let O be the origin, the point A be the point be such that and . Then

(A)
area of triangle ABO is
(B)
ABO is an obtuse angled isosceles triangle
(C)
area of triangle ABO is
(D)
ABO is a scalene triangle