Sigma Percentile
JEE Main 2004
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: Let and be complex numbers such that and . Then equals

Select Answer:

Visualized Solution

Visualizing the Complex Plane

  • Given equations:
  • 1.
  • 2.
  • Objective: Find

Simplifying the First Equation

  • Take the conjugate of :
  • Using properties: and
  • Result:

Applying the Conjugate Property

  • Let's apply this conjugate property directly to our equation.
  • We take the conjugate of the entire left-hand side:
  • Since is a real number, its conjugate remains .

Atomic Compute: Simplifying the Conjugate

  • Simplify step-by-step:
  • Since , , and :

Relating and Geometrically

  • Rearrange the equation:
  • This implies is obtained by rotating by counter-clockwise.

Applying Argument Properties

  • Using :
  • Since :

Expressing in terms of

  • From :
  • Since lies on the positive imaginary axis, :

Using the Second Condition

  • From the second given condition:
  • Using product property:

Solving the System of Equations

  • Substitute into the sum:
  • Combine like terms:

Calculating the Final Value

  • Add to both sides:
  • Divide by :

Conclusion and Key Takeaways

  • Key Takeaways:
  • * Multiplication by represents a rotation.
  • * Argument properties transform complex multiplication into addition.
  • Therefore, the correct option is .

The Sigma Insight: Argand Plane and Polar Representation

Solution Diagram

Analyzing the Conjugate Mystery

We are given the equation . To isolate the variables, we take the conjugate of the entire equation:
Using the fundamental properties of conjugates, where the conjugate of a sum is the sum of the conjugates and the conjugate of a product is the product of the conjugates, we simplify the expression. Recall that , , and .
This transforms our equation into:

The Geometric Insight

In the complex plane, multiplying a number by is a geometric transformation. Since , multiplying by is equivalent to a counter-clockwise rotation by radians (or ).
This means the vector representing is simply the vector rotated by . Whenever you encounter in a complex number problem, always consider the geometric rotation it represents.

The Argument Algebra

We are given the condition . Using the property that the argument of a product is the sum of the arguments, we have:
From our earlier relation , we apply the argument property again:
Since lies on the positive imaginary axis, its argument is . Substituting this, we get:

Final Calculation

We now have a system of two linear equations: 1) 2)
Adding these two equations together yields:
Dividing by 2, we find the final result:
The key to mastering these problems is to look for the geometric meaning behind the algebraic symbols. By combining the properties of conjugates with the rotational nature of complex multiplication, we arrive at the solution of .

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