Sigma Percentile
JEE Main 2023 (25 January Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Differentiation: Let . Then at is equal to

Select Answer:

Visualized Solution

Analyzing the Function

  • Given function:
  • The exponents of follow a geometric progression: .
  • Direct differentiation using the product rule would be highly complex.

The Telescoping Identity

  • Recall the algebraic identity:
  • To utilize this, we multiply and divide the entire expression by .

Collapsing the Product

  • Applying the identity repeatedly:
  • Continuing this chain reaction up to .

Simplified Form of

  • The numerator collapses entirely to .
  • Simplified expression:
  • Rearranging to avoid the quotient rule during differentiation:

First Differentiation

  • Differentiating with respect to :
  • Using the product rule on :

Second Differentiation

  • Differentiating again with respect to :

Evaluating

  • We need values at .
  • From the original function:
  • Since the first term , the entire product becomes zero.

Evaluating

  • Substitute and into the first derivative equation:

Evaluating

  • Substitute and into the second derivative equation:

Final Calculation

  • Final expression to evaluate:
  • Substitute the calculated values:
  • The correct option is 496.

The Sigma Insight: Techniques of Differentiation

Analyzing the Setup

Imagine you are standing before a massive, intimidating product:
At first glance, it looks like a monster. If you try to attack this with the product rule, you will find yourself drowning in a sea of terms.
In the world of JEE Advanced, we don't fight monsters with brute force; we fight them with insight. Notice the exponents: . They are powers of , forming a classic geometric progression.
Whenever you see a product of terms like , your mind should immediately jump to the difference of squares identity:
This is our secret weapon.

The Chain Reaction

To unlock the potential of this identity, we perform a clever maneuver. We multiply and divide the entire expression by .
Now, look at what happens: the numerator becomes . The first two terms collapse into .
Then, collapses into . This chain reaction continues, with each step doubling the power of , until the entire numerator simplifies to .
Our function is now:

The Elegance of Implicit Differentiation

Now, we could use the quotient rule, but why make life difficult? Let's rearrange the equation:
This gives us . This is much friendlier.
Differentiating with respect to , we get:
Differentiating once more, we get:

The Final Evaluation

We need to evaluate this at . First, because the original product contains , which becomes .
Substituting and into our first derivative equation:
Now, for the second derivative:
This simplifies to , so .
Finally, the question asks for at . That is:
We have tamed the monster, and the result is a beautiful, clean integer. This is the power of pattern recognition in mathematics. The final answer is 496.

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