Sigma Percentile
JEE Advanced 2023
LEVELJEE Main

Animated Solution for Mathematics - Limits, Continuity and Differentiability: Let and . Then which of the following statements is(are) true ?

Select Answer:

* Multiple Correct

Visualized Solution

Visualizing Domain and Codomain

  • Domain:
  • Codomain:

Total Number of Functions (Setup)

  • Number of points in is infinite.
  • Choices in for each point = .

Total Number of Functions (Compute)

  • Total functions =
  • Option (A) is True.

Strictly Increasing Functions (Logic)

  • Condition for strictly increasing:
  • If , then .

Strictly Increasing Functions (Compute)

  • has infinite points, but has only elements.
  • Impossible to assign strictly increasing values.
  • Option (B) is False.

Continuous Functions (Logic)

  • For to be continuous, it cannot take values between the discrete points of .

Constant on Connected Components

  • must be constant on each connected component of .

Counting Continuous Functions

  • Connected components of : , , .
  • Choices for each component = .
  • Total continuous functions = .

Continuous Functions Conclusion

  • Option (C) is True.

Differentiability (Logic)

  • Every continuous function is piecewise constant.

Differentiability Conclusion

  • Derivative of a constant:
  • is differentiable everywhere on .
  • Option (D) is True.

The Sigma Insight: Relationship Between Continuity and Differentiability

Solution Diagram

Analyzing the Setup

We are given a domain , which consists of three disjoint open intervals. The codomain is a discrete set .
The tension in this problem arises from mapping an uncountable set of points in to a finite, discrete set of points in .

Evaluating Option A

Total Number of Functions
A function assigns one of the 4 values from to every point in . Since contains infinitely many points, we are making an infinite number of independent choices.
The total number of such functions is given by:
This value is clearly infinite. Therefore, Option A is true.

Evaluating Option B

Strictly Increasing Functions
For a function to be strictly increasing, the condition must imply .
If we attempt to map the infinite points of any interval in to the set , we would require a unique, strictly larger value for every point. Since only contains 4 elements, we would exhaust the available values immediately.
Thus, it is impossible to construct a strictly increasing function. Option B is false.

Evaluating Option C

Continuous Functions
According to the Intermediate Value Theorem, a continuous function must map a connected interval to a connected set. Since is a discrete set, the only connected subsets of are singletons (sets containing exactly one point).
Consequently, any continuous function must be constant on each connected component of . The components are , , and .
For each of the 3 components, we have 4 possible constant values to choose from. The total number of continuous functions is:
Since , Option C is true.

Evaluating Option D

Differentiability
We have established that any continuous function must be piecewise constant. Specifically, on each interval, for some .
The derivative of a constant function is zero:
Since the derivative exists and is equal to for all , the function is differentiable. Therefore, Option D is true.

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