Analyzing the Setup
We are given a domain S=(0,1)∪(1,2)∪(3,4), which consists of three disjoint open intervals. The codomain is a discrete set T={0,1,2,3}.
The tension in this problem arises from mapping an uncountable set of points in S to a finite, discrete set of points in T.
Evaluating Option A
Total Number of Functions
A function f:S→T assigns one of the 4 values from T to every point in S. Since S contains infinitely many points, we are making an infinite number of independent choices.
The total number of such functions is given by:
This value is clearly infinite. Therefore, Option A is true.
Evaluating Option B
Strictly Increasing Functions
For a function to be strictly increasing, the condition x1<x2 must imply f(x1)<f(x2).
If we attempt to map the infinite points of any interval in S to the set {0,1,2,3}, we would require a unique, strictly larger value for every point. Since T only contains 4 elements, we would exhaust the available values immediately.
Thus, it is impossible to construct a strictly increasing function. Option B is false.
Evaluating Option C
Continuous Functions
According to the Intermediate Value Theorem, a continuous function must map a connected interval to a connected set. Since T is a discrete set, the only connected subsets of T are singletons (sets containing exactly one point).
Consequently, any continuous function f must be constant on each connected component of S. The components are (0,1), (1,2), and (3,4).
For each of the 3 components, we have 4 possible constant values to choose from. The total number of continuous functions is:
Since 64≤120, Option C is true.
Evaluating Option D
Differentiability
We have established that any continuous function f:S→T must be piecewise constant. Specifically, on each interval, f(x)=c for some c∈{0,1,2,3}.
The derivative of a constant function is zero:
Since the derivative exists and is equal to 0 for all x∈S, the function is differentiable. Therefore, Option D is true.