Animated Solution for Mathematics - Limits, Continuity and Differentiability: The function f(x)=max{(1−x),(1+x),2},x∈(−∞,∞) is
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Visualized Solution
Understanding the Maximum Function f(x)
The function is defined as f(x)=max{(1−x),(1+x),2} for all real x.
This means at any point x, the value of f(x) is the largest of the three values: 1−x, 1+x, and 2.
To analyze continuity and differentiability, we will visualize this geometrically by plotting each component.
Plotting the Line y=1−x
Let's analyze the first candidate: y1=1−x.
This is a straight line with a slope of −1 and a y-intercept of 1.
It passes through key points like (0,1) and (−1,2).
Plotting the Line y=1+x
Next, consider the second candidate: y2=1+x.
This is a straight line with a positive slope of 1 and a y-intercept of 1.
It passes through key points like (0,1) and (1,2).
Plotting the Constant Line y=2
The third candidate is the constant function: y3=2.
This is a horizontal line parallel to the x-axis at a height of 2 units.
It intersects y1=1−x at x=−1 and y2=1+x at x=1.
Finding the Maximum Envelope
The function f(x) selects the maximum value among the three at any x.
This corresponds to the uppermost boundary (the upper envelope) of the three lines.
Let's trace this upper boundary across different intervals of x.
Piecewise Definition of f(x)
For x<−1: The line y=1−x is the highest.
For −1≤x≤1: The horizontal line y=2 is the highest.
For x>1: The line y=1+x is the highest.
Thus, we can write f(x) piecewise as: f(x)=⎩⎨⎧1−x,2,1+x,x<−1−1≤x≤1x>1
Checking Continuity
A function is continuous if its graph has no breaks, holes, or jumps.
At x=−1: Left-hand limit is 1−(−1)=2, and right-hand limit is 2.
At x=1: Left-hand limit is 2, and right-hand limit is 1+1=2.
Since the limits match the function values at the boundary points, f(x) is continuous everywhere.
Differentiability at x=−1
Differentiability requires the slope to be unique and well-defined (no sharp corners).
Left-Hand Derivative (LHD) at x=−1: dxd(1−x)=−1.
Right-Hand Derivative (RHD) at x=−1: dxd(2)=0.
Since LHD=RHD, f(x) is not differentiable at x=−1.
Differentiability at x=1
Let's check the other boundary point, x=1.
Left-Hand Derivative (LHD) at x=1: dxd(2)=0.
Right-Hand Derivative (RHD) at x=1: dxd(1+x)=1.
Since LHD=RHD, f(x) is not differentiable at x=1.
Final Verdict and Summary
The function f(x) is continuous at all points in (−∞,∞).
The function is differentiable at all points except at x=1 and x=−1.
Therefore, the correct options are continuous at all points and differentiable at all points except at x=1 and x=−1.
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The Sigma Insight: Relationship Between Continuity and Differentiability
The Geometry of Choices
Unveiling the Max Function
Imagine you are walking along a mountain range. At any point in your journey, you are standing on the highest peak available to you.
This is exactly what the function f(x)=max{(1−x),(1+x),2} represents. It is a decision-maker, a selector that constantly chooses the largest value among three competing paths.
To master this, we must stop thinking of it as a scary algebraic expression and start seeing it as a landscape.
The Three Contenders
Let us introduce our three contenders. First, we have y1=1−x, a line descending with a slope of −1. It is a steady decline, passing through (−1,2) and (0,1).
Second, we have y2=1+x, a line ascending with a slope of 1, passing through (0,1) and (1,2). Finally, we have the steady, unwavering y3=2, a horizontal line that refuses to change regardless of x.
To find f(x), we are looking for the 'upper envelope.' Imagine a spotlight shining from above; the graph of f(x) is the shadow cast by the highest line at any given x.
Mapping the Landscape
As we move from x=−∞ toward the right, we see that 1−x starts very high. But as x increases, 1−x drops. Meanwhile, 2 stays constant.
At x=−1, the line 1−x hits the value 2. Before x=−1, 1−x is greater than 2. After x=−1, the constant 2 becomes the dominant force.
Similarly, as we approach x=1, the constant 2 is still the highest, but once we cross x=1, the line 1+x begins to climb higher than 2. Thus, our function reveals its true piecewise nature:
f(x)=⎩⎨⎧1−x,2,1+x,x<−1−1≤x≤1x>1
The Test of Continuity
Continuity is the soul of a graph—it asks, 'Is there a break in the path?' Let us check the transition points.
At x=−1, the left-hand limit is 1−(−1)=2, and the right-hand limit is 2. They meet perfectly!
At x=1, the left-hand limit is 2, and the right-hand limit is 1+1=2. Again, they meet. Because the pieces connect without any jumps, the function is continuous everywhere. You can draw this graph without ever lifting your pen from the paper.
The Sharp Reality of Differentiability
Now, we reach the most exciting part: differentiability. Differentiability is about smoothness. A function is differentiable only if it has a unique, well-defined slope at every point.
At x=−1, the slope to the left is:
dxd(1−x)=−1
But the slope to the right is:
dxd(2)=0
Because $-1
eq 0$, the graph has a sharp 'kink' at x=−1. The same happens at x=1, where the slope changes from 0 to 1.
These sharp corners are the 'traps' of calculus. They are continuous, yes, but they are not smooth. Therefore, while the function is continuous at all points, it fails the test of differentiability at x=−1 and x=1.
The Final Insight
By visualizing the function as an upper envelope, we transformed a daunting algebraic problem into a clear geometric story.
We learned that continuity is about connection, while differentiability is about the grace of a smooth curve. You have successfully navigated the landscape of this function, proving that with the right perspective, even the most complex piecewise definitions become intuitive and elegant.