Analyzing the Setup
In the world of calculus, continuity is the ultimate test of structural integrity. Imagine a function as a road; if you reach x=0, you expect a smooth transition. If there is a gap, a jump, or a hole, the function is discontinuous.
Our mission is to find the values of a and b that ensure this bridge is perfectly connected at x=0.
The Left Hand Limit
The 1∞ Beast
As we approach x=0 from the left, we encounter the expression f(x)={1+∣sinx∣}∣sinx∣a. As x→0−, the base 1+∣sinx∣ approaches 1, while the exponent ∣sinx∣a approaches infinity.
We have arrived at the classic
1∞ indeterminate form. We utilize the standard limit shortcut:
x→clim(1+g(x))h(x)=elimx→cg(x)h(x)
Here,
g(x)=∣sinx∣ and
h(x)=∣sinx∣a. When we multiply these terms, the
∣sinx∣ components cancel out with surgical precision:
x→0−limf(x)=elimx→0−(∣sinx∣⋅∣sinx∣a)=ea
Thus, our Left Hand Limit is simply ea.
The Right Hand Limit
The Trigonometric Dance
Now, we shift our gaze to the right side of the bridge, where x>0. Here, the function takes the form f(x)=etan3xtan2x.
We need to evaluate the limit of the exponent: limx→0+tan3xtan2x. Plugging in x=0 yields the 00 indeterminate form.
We apply the standard limit
limθ→0θtanθ=1 by performing an algebraic maneuver:
x→0+limtan3xtan2x=x→0+lim(2xtan2x)⋅(tan3x3x)⋅(3x2x)
As x→0, the first two terms approach 1, and the x variables cancel out. This leaves us with a limit of 32. Therefore, our Right Hand Limit is e32.
The Grand Unification
For the function to be continuous at
x=0, the Left Hand Limit, the Right Hand Limit, and the function value
f(0)=b must all be equal. This gives us the condition:
ea=e32=b
By comparing the exponents, we find:
a=32
By comparing the values, we find:
b=e32
You have successfully bridged the gap, solved the indeterminate forms, and mastered the continuity of this function. Keep this mindset—every complex problem is just a bridge waiting for you to connect the pieces.