Sigma Percentile
JEE Main 2022 (29 June Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: Let and be the roots of the equation . Then, the value of is equal to :

Select Answer:

Visualized Solution

Given Equation

  • Given equation:
  • Roots are and

Isolating

  • Rearranging the terms:

Roots and

  • Since are roots:

Calculating and

  • Using exponent rules:
  • Similarly,

Sum

  • Summing the terms:

Modulus Property

  • We need
  • Using :

Modulus of

  • Calculating :

Final Computation

  • Substituting back:

The Sigma Insight: Algebraic Operations on Complex Numbers

Solution Diagram

Analyzing the Setup

We are given the quadratic equation . We need to determine the value of , where and are the roots of this equation.
Many students instinctively reach for the quadratic formula, but this often leads to unnecessary complexity. Instead, we should focus on the structural properties of the equation.

The Power of Isolation

By rearranging the given equation, we isolate the squared term:
Since and are the roots of the equation, they must satisfy this relationship. Therefore, we have:
Notice the symmetry here: both roots yield the same value when squared. This observation allows us to bypass the need to calculate the individual roots and .

Bridging the Gap

To find and , we raise our squared expression to the fourth power. Since , it follows that:
Applying the same logic to , we find:

The Modulus Magic

We now calculate the modulus of the sum:
Using the properties of the modulus, specifically and , we simplify the expression:
Next, we calculate the modulus of the complex number :

The Grand Finale

Substituting the value of the modulus back into our expression, we get:
Since , the final calculation is:
By identifying the underlying symmetry and utilizing the properties of complex numbers, we have determined that the final answer is 50.

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