Animated Solution for Mathematics - Sets and Relations: Let A={1,2,3,…,7} and let P(A) denote the power set of A. If the number of functions f:A→P(A) such that a∈f(a),∀a∈A is mn,m and n∈N and m is least, then m+n is equal to ______
Enter Numerical Value:
Visualized Solution
Defining Set A
Given set A={1,2,3,…,7}
Number of elements in A, n(A)=7
The Power Set P(A)
P(A) is the power set of A
It contains all possible subsets of A
Total elements in P(A)=27=128
The Function Mapping
We are forming functions f:A→P(A)
Each element in A maps to exactly one subset in P(A)
The Constraint a∈f(a)
The problem imposes a strict condition: a∈f(a)
The image of a must be a subset that contains a itself
Valid Subsets for Element a
How many subsets in P(A) contain a specific element a?
Fix a in the subset. The remaining 6 elements can be chosen in 26 ways.
Number of valid choices for f(a)=26=64
Total Number of Functions
Each of the 7 elements in A has 26 independent choices
Total functions =26×26×⋯×26 (7 times)
Total functions =(26)7=242
Identifying m and n
We are given that the total number of functions is mn
So, mn=242
We need the least natural number m
Since m∈N and m=1 (as 1n=242), the least m is 2
Therefore, m=2 and n=42
Final Calculation
We need to find the value of m+n
m+n=2+42=44
Final Answer: 44
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The Sigma Insight: Types of Sets and Set Operations
Solution Diagram
Analyzing the Setup
We are tasked with finding the number of functions f:A→P(A) where A={1,2,3,…,7}, subject to the constraint that for every a∈A, a∈f(a). Here, P(A) denotes the power set of A.
The set A contains n=7 elements. The power set P(A) contains 2n=27=128 distinct subsets.
The Constraint
A Filter of Possibility
Consider a single element a∈A. The condition a∈f(a) implies that the subset f(a) must contain the element a.
To determine the number of such subsets, we fix a as an element of the subset. For the remaining n−1=6 elements of A, each element has exactly 2 choices: it can either be included in the subset or excluded.
Thus, the number of valid subsets f(a) for any specific a is:
2n−1=27−1=26=64
The Master Equation
Since there are 7 elements in A, and each element a must independently choose a subset f(a) from the 64 valid options, we apply the fundamental principle of counting. The total number of such functions is the product of the number of choices for each of the 7 elements.
The total number of functions is given by:
Total=7 times26×26×⋯×26=(26)7
Applying the laws of exponents, we simplify this expression:
Total=26×7=242
Final Calculation
We are asked to express this result in the form mn, where m is the least natural number. Given mn=242, we seek the smallest possible base m.
The smallest prime base for this power is m=2, which corresponds to n=42.