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Visualized Solution
The Sigma Insight: d-block Elements
The Battle of the Ions
Ferrous vs. Ferric
When iron enters the chemical arena, it primarily does so in two distinct avatars: the oxidation state (Ferrous, ) and the oxidation state (Ferric, ). While they are born from the same parent atom, the loss of that one extra electron in drastically alters its chemical personality. To understand why, we need to unlock the secrets of Fajans' Rule.
Fajans' Rule
The Master Key
Fajans' Rule is a beautiful concept that bridges the gap between purely ionic and purely covalent bonds. It states that no bond is ionic. Every cation has a tendency to distort the electron cloud of a neighboring anion, pulling it towards itself. This phenomenon is called polarization.
The polarizing power of a cation depends on two critical factors: its charge and its size. A higher positive charge acts like a stronger magnet, while a smaller size allows the cation to get closer to the anion's electron cloud. Therefore, Polarizing Power .
When we compare and , the Ferric ion () has a higher charge () and a smaller ionic radius. Consequently, possesses a significantly higher polarizing power. It distorts the anion's electron cloud much more effectively, leading to a greater sharing of electrons. Thus, compounds are predominantly covalent, while compounds are predominantly ionic.
Decoding the Properties
Basicity, Volatility, and Hydrolysis
Now that we have established the ionic/covalent nature of these compounds, let's evaluate the given statements one by one.
1. Basic Nature of Oxides:
The basicity of a metal oxide is directly linked to its ionic character. An ionic oxide easily dissociates in water to release oxide ions (), which then form hydroxide ions (), making the solution basic. Since forms more ionic compounds, Ferrous oxide () is more basic than Ferric oxide (). Statement (a) is correct.
2. Ionic Character:
As derived directly from Fajans' Rule, the lower oxidation state () results in less polarization. Therefore, Ferrous compounds are relatively more ionic than Ferric compounds. Statement (b) is correct.
3. Volatility:
Volatility refers to how easily a substance vaporizes. Ionic compounds are held together by strong, extensive electrostatic forces in a rigid crystal lattice, making them highly non-volatile. Covalent compounds, however, exist as discrete molecules held together by weaker intermolecular forces (like Van der Waals forces), making them relatively more volatile. Since Ferrous compounds are more ionic, they are less volatile than the corresponding Ferric compounds. Statement (c) is correct.
4. Hydrolysis:
Hydrolysis is the chemical breakdown of a compound due to reaction with water. Covalent metal halides (like ) undergo hydrolysis much more readily than ionic halides (like ). The high charge density on the ion strongly attracts the oxygen atom of water molecules, facilitating the breaking of bonds and the formation of bonds. Therefore, Ferric compounds are more easily hydrolysed.
The Final Verdict
Statement (d) claims that "Ferrous compounds are more easily hydrolysed than the corresponding ferric compounds." Based on our analysis of Fajans' Rule and the nature of hydrolysis, this is the exact opposite of the truth. Ferric compounds are the ones that hydrolyse more easily.
Thus, statement (d) is the incorrect statement, making it the right answer to our question.
Similar Questions
JEE Main 2021
LEVELJEE Main
The correct order of following -metal oxides, according to their oxidation numbers is (A) (B) (C) (D) (E)
(A)
(D) > (A) > (B) > (C) > (E)
(B)
(A) > (C) > (D) > (B) > (E)
(C)
(A) > (D) > (C) > (B) > (E)
(D)
(C) > (A) > (D) > (E) > (B)
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The element that usually does not show variable oxidation states is
(A)
Sc
(B)
Cu
(C)
Ti
(D)
V
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The nature of oxides and is indexed as 'X' and 'Y' type respectively. The correct set of X and Y is
(A)
X = basic, Y = amphoteric
(B)
X = amphoteric, Y = basic
(C)
X = acidic, Y = acidic
(D)
X = basic, Y = basic
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LEVELJEE Main
The oxide that shows magnetic property is
(A)
(B)
(C)
(D)
JEE Main 2021
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In the given chemical reaction, colours of the and ions, are respectively
(A)
yellow, orange
(B)
yellow, green
(C)
green, orange
(D)
green, yellow
JEE Main 2020
LEVELJEE Main
The incorrect statement(s) among (1)-(3) is (are) 1. W(VI) is more stable than Cr(VI). 2. in the presence of HCl, permanganate titrations provide satisfactory results. 3. some lanthanoid oxides can be used as phosphors.
(A)
2 and 3 only
(B)
2 only
(C)
1 only
(D)
1 and 2 only
JEE Advanced 2019
LEVELJEE Advanced
Fusion of with in presence of produces a salt . Alkaline solution of upon eletrolytic oxidation yields another salt . The manganese containing ions present in and , respectively, are and . Correct statement(s) is (are)
* Multiple Correct Options
(A)
is diamagnetic in nature while is paramagnetic
(B)
Both and are coloured and have tetrahedral shape
(C)
In both and , -bonding occurs between p-orbitals of oxygen and d-orbitals of manganese.
(D)
In aqueous acidic solution, undergoes disproportionation reaction to give and .
JEE Main 2020
LEVELJEE Main
The incorrect statement is :
(A)
Manganate ion is green in colour and permanganate ion is purple in colour.
(B)
Manganate and permanganate ions are paramagnetic.
(C)
In manganate and permanganate ions, the -bonding takes place by overlap of p-orbitals of oxygen and d-orbitals of manganese.
(D)
Manganate and permanganate ions are tetrahedral.
LEVELJEE Main
In context with the transition elements, which of the following statements is incorrect?
(A)
In addition to the normal oxidation state, the zero oxidation state is also shown by these elements in complexes
(B)
In the highest oxidation states, the transition metal shows basic character and form cationic complexes
(C)
In the highest oxidation states of the first five transition elements (Sc to Mn), all the and electrons are used for bonding
(D)
Once the configuration is exceeded, the tendency to involve all the electrons in bonding decreases
JEE Main 2019
LEVELJEE Main
The statement that is incorrect about the interstitial compounds is
(A)
they are very hard
(B)
they have metallic conductivity
(C)
they have high melting points
(D)
they are chemically reactive
