The Magic of Transition Metal Colors
Have you ever wondered why chemistry labs are filled with such vibrant, colorful solutions? The secret often lies within the d-block elements! In this problem, we are looking at a classic redox titration reaction between ferrous ions and permanganate ions in an acidic medium.
5Fe2++MnO4−+8H+⟶Mn2++4H2O+5Fe3+
This equation might look like a mouthful, but it tells a beautiful story of electron transfer. The permanganate ion (MnO4−) acts as a powerful oxidizing agent. It aggressively pulls electrons away from the iron, forcing it to jump from a +2 oxidation state to a +3 oxidation state.
The Ferrous State
A Pale Green
Let's focus on our starting material, the ferrous ion (Fe2+). When you dissolve a ferrous salt, like Mohr's salt or ferrous sulfate, in water, you are greeted with a characteristic pale green solution.
Why green? It all comes down to the electronic configuration. The Fe2+ ion has a [Ar]3d6 configuration. When water molecules surround this ion, they split the energy levels of those d-orbitals. As light passes through the solution, the electrons absorb specific wavelengths to jump between these split levels (a phenomenon known as d-d transitions). The light that isn't absorbed—the light that reaches our eyes—appears green.
The Ferric State
A Shift to Yellow
As the reaction proceeds, the Fe2+ loses an electron and transforms into the ferric ion (Fe3+). This tiny loss of a single electron has a dramatic visual effect!
The new configuration is [Ar]3d5. Because the number of electrons has changed, the energy gap between the split d-orbitals also changes. The ion now absorbs a different set of wavelengths from the visible spectrum. Consequently, aqueous solutions containing Fe3+ ions typically exhibit a yellow or yellowish-brown color.
The Final Verdict
By simply tracking the oxidation states and recalling our laboratory observations, we can confidently determine the colors. The reactant Fe2+ is green, and the product Fe3+ is yellow.
Therefore, the correct sequence of colors is green, yellow, which perfectly matches option (d).
Bonus Insight: While the question focuses on iron, don't forget the star of the show—the permanganate ion! It starts as a brilliant, deep purple and turns practically colorless as it reduces to Mn2+. This dramatic color change is exactly why KMnO4 is used as a self-indicator in redox titrations. No extra indicator drops needed!