Analyzing the Setup
We are tasked with finding the Boolean operators ⊕ and ⊙ such that the expression (p⊕q)∧(∼p⊙q) is logically equivalent to the intersection p∧q.
The target expression p∧q represents the region where both p and q are true. Our objective is to identify the specific operators that reduce the given compound statement to this intersection.
Testing the Hypothesis
Let us test the candidate operators: ⊕=∧ and ⊙=∨. Substituting these into the original expression, we obtain:
To simplify this, we apply the Distributive Law. We distribute the term (p∧q) over the disjunction (∼p∨q) as follows:
The Surgical Simplification
We now evaluate the two resulting terms independently to determine their truth values.
The First Term: ((p∧q)∧∼p). By applying the Associative Law, we rearrange this to (p∧∼p)∧q. Since p∧∼p is a contradiction (always False), the entire term simplifies to F∧q, which is F.
The Second Term: (p∧q)∧q. Using the Associative Law, we rewrite this as p∧(q∧q). By the Idempotent Law, q∧q simplifies to q, leaving us with p∧q.
Final Calculation
Combining these results, the expression becomes F∨(p∧q).
By the Identity Law, the disjunction of False with any expression is the expression itself. Thus, the entire statement simplifies to:
This matches our target perfectly. We have confirmed that the ordered pair (∧,∨) is the correct solution.