Sigma Percentile
JEE Main 2021 (February) (25 Feb Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Differentiation: If Rolle's theorem holds for the function with , then ordered pair is equal to :

Select Answer:

Visualized Solution

The Setup: Rolle's Theorem

  • Function:
  • Interval:
  • Goal: Find the ordered pair

Condition 1: Equal Endpoints

  • For Rolle's Theorem to hold, the function values at the endpoints must be equal.
  • Therefore, .

Substituting Endpoints

  • Substitute :
  • Substitute :
  • Equating them:

Simplifying Equation 1

  • Left side:
  • Right side:
  • Rearranging terms: (Equation 1)

Condition 2: The Horizontal Tangent

  • Rolle's Theorem guarantees a point where .
  • Given: .
  • This means the tangent is horizontal at .

Finding the Derivative

  • Differentiating with respect to .

Substituting

  • We know .
  • Substitute into the derivative:

Simplifying Equation 2

  • Multiply the entire equation by to clear denominators:
  • Rearranging: (Equation 2)

Solving the System of Equations

  • We now have a system of two linear equations:
  • 1)
  • 2)
  • Multiply Equation 1 by :

Finding the value of

  • Modified Eq 1:
  • Equation 2:
  • Subtracting Eq 2 from Modified Eq 1:

Finding the value of

  • Substitute into Equation 1:

Final Answer

  • The ordered pair is .
  • Key Takeaway: Rolle's Theorem links the equality of boundary values to the existence of a horizontal tangent inside the interval.

The Sigma Insight: Mean Value Theorems

Solution Diagram

The Elegant Dance of Rolle's Theorem

Imagine you are standing on a mountain path. You start at an elevation of meters at point , and after a long, winding hike, you find yourself back at an elevation of meters at point .
Logic dictates that at some point during your journey, you must have either climbed up and then back down, or descended and then climbed back up. In either case, there was a moment where your path was perfectly level—a horizontal tangent. This is the physical soul of Rolle's Theorem.

The Mathematical Blueprint

We are given the cubic function on the interval . For Rolle's Theorem to hold, we require two fundamental conditions.
First, the function must be continuous and differentiable (which, being a polynomial, it is). Second, the values at the boundaries must be identical: .
Let us calculate these values. Substituting into our function, we get:
Now, for , we have:
Setting these equal, we arrive at our first vital equation:

The Power of the Derivative

Now, we turn to the second condition: the existence of a horizontal tangent. We are told that .
To find this, we differentiate our function:
By substituting into this derivative, we get:
Simplifying this, we have , which reduces to . Multiplying by to clear the fractions, we obtain our second equation:

The Final Resolution

We are left with a system of two linear equations:
To solve this, we multiply the first equation by to get . Now, subtracting the second equation from this, we see the terms vanish:
This calculation yields . Substituting back into our first equation, , we find , leading to .
We have successfully navigated the constraints of the theorem to find that . It is a beautiful reminder that even in the abstract world of calculus, every equation has a physical story to tell.

Similar Questions

JEE Main 2020 - 8 Jan (Morning)
LEVELJEE Main

If is a point at which Rolle's theorem holds for the function, in the interval , where , then is equal to :

(A)
(B)
(C)
(D)
JEE Advanced 2004
LEVELJEE Main

If and , then the value of for which Rolle's theorem can be applied in is

(A)
(B)
(C)
(D)
JEE Advanced 2003
LEVELJEE Main

If the function is differentiable then show that (i) For

JEE(ADVANCED)-201
LEVELJEE Advanced

For every twice differentiable function with , which of the following statement(s) is (are) TRUE ?

* Multiple Correct Options
(A)
There exist , where , such that is one-one on the open interval
(B)
There exists such that
(C)
(D)
There exist such that and
JEE Main 2012
LEVELJEE Main

Consider the function, . Statement-1 : . Statement-2 : is continuous in , differentiable in and .

(A)
Statement-1 is false, Statement-2 is true.
(B)
Statement-1 is true, Statement-2 is true; statement-2 is a correct explanation for Statement-1.
(C)
Statement-1 is true, Statement-2 is true; statement-2 is not a correct explanation for Statement-1.
(D)
Statement-1 is true, Statement-2 is false.
JEE Advanced 2004
LEVELJEE Main

Using Rolle's theorem, prove that there is at least one root in of the polynomial .

JEE Main 2020 - 4 Sep (Morning)
LEVELJEE Main

Let be a twice differentiable function on . If , , and for all , then :

(A)
(B)
(C)
(D)
JEE Main 2005
LEVELJEE Main

Let be differentiable for all . If and for , then

(A)
f(6) \geq 8
(B)
f(6) < 8
(C)
f(6) < 5
(D)
f(6) = 5
JEE Main 2020 (9 January Shift 1)
LEVELJEE Advanced

Let be any function continuous on and twice differentiable on . If for all , and , then for any , is greater than:

(A)
(B)
(C)
(D)
JEE Main 2014
LEVELJEE Main

If and are differentiable functions in satisfying and , then for some

(A)
f'(c) = g'(c)
(B)
f'(c) = 2g'(c)
(C)
2f'(c) = g'(c)
(D)
2f'(c) = 3g'(c)