Analyzing the Setup
We are tasked with analyzing the function defined by the integral:
g(x)=∫0xcos(4t)dt
Think of this as an area function. The graph of y=cos(4t) is a wave oscillating with a frequency four times higher than the standard cosine wave. As x increases, we accumulate the signed area under this wave.
The Integration
A Step of Precision
To find the explicit form of g(x), we apply the fundamental theorem of calculus. Using the rule ∫cos(at)dt=asin(at), where a=4, we perform the integration:
Applying the limits from 0 to x, we obtain:
Since sin(0)=0, the function simplifies to the elegant expression:
The Shift
Exploring g(x+π)
Next, we investigate the behavior of g(x+π) by substituting the shifted value into our derived function:
g(x+π)=4sin(4(x+π))=4sin(4x+4π)
Recall that the sine function is periodic with a period of 2π. Because 4π represents exactly two full cycles, the sine function remains unchanged:
Therefore, we conclude that:
The Final Revelation
To finalize our understanding, we evaluate g(π) by substituting π into our formula:
This result reveals a profound geometric truth: the integral of cos(4t) over the interval [0,π] covers exactly two full periods of the wave. Consequently, the positive and negative areas cancel out perfectly.
Given that g(π)=0, we observe that:
Both expressions are equivalent to g(x), demonstrating the inherent symmetry and periodic nature of the function.