Animated Solution for Mathematics - Sequence and Series: If an=7+7+7+.... having n radical signs then by methods of mathematical induction which is true
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Visualized Solution
The Nested Radical Sequence
Given sequence: an=7+7+…
The sequence has n radical signs.
We need to find an upper bound using Mathematical Induction.
Recursive Definition
Let's write the first few terms.
a1=7
a2=7+7=7+a1
General recursive relation: an+1=7+an
Graphical Perspective
Let y=7+x represent our recursive function.
The line y=x helps us map an to an+1.
The sequence terms can be visualized as a cobweb plot.
Base Case (n=1)
We will test the inequality an<7.
For n=1:
a1=7
Evaluating the Base Case
We know that 2<7<3.
Therefore, a1=7<7.
The base case holds true!
Inductive Hypothesis
Assume the statement is true for some integer n=k.
Assumption:ak<7
Inductive Step Goal
We must prove the statement is true for n=k+1.
To Prove:ak+1<7
Applying the Recursive Formula
Recall the recursive relation:
ak+1=7+ak
Building the Inequality
From our assumption:
ak<7
Adding 7 to Both Sides
Add 7 to both sides of the inequality:
7+ak<7+7
7+ak<14
Taking the Square Root
Take the positive square root on both sides:
7+ak<14
Finalizing the Inductive Step
We know 14≈3.74, which is strictly less than 7.
Therefore, 7+ak<7
This means ak+1<7.
Conclusion
By the Principle of Mathematical Induction, an<7 for all n≥1.
The sequence is bounded above by 7.
Correct Option:an<7∀n≥1
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The Sigma Insight: Sum of Special Series
Solution Diagram
Analyzing the Recursive Heart
Let us define our sequence an=7+7+… with n radical signs. If you look closely, you will see a beautiful self-similarity.
The term a2 is 7+7, which is just 7+a1. Similarly, a3 is 7+a2.
This reveals the recursive soul of our sequence:
an+1=7+an
This simple relation is the key to everything. We are not dealing with a static number; we are dealing with a dynamic process where each term feeds into the next.
The Domino Effect
Mathematical Induction is like a row of dominoes. If we can prove that the first domino falls (the base case) and that one falling domino will always knock over the next (the inductive step), then the entire sequence must fall into place.
For our base case, n=1, we have a1=7. Since 22=4 and 32=9, we know that 2<7<3.
Thus, a1<7. The first domino has fallen!
The Inductive Leap
Now, we assume the statement is true for some integer k, meaning we assume ak<7. This is our inductive hypothesis.
Our mission is to prove that ak+1<7. We start with our assumption: ak<7.
First, add 7 to both sides:
7+ak<7+7
7+ak<14
Now, take the square root of both sides:
7+ak<14
Since 14≈3.74, and 3.74<7, we have successfully shown that ak+1<7.
The Grand Conclusion
By the Principle of Mathematical Induction, we have proven that an<7 for all n≥1.
We have taken a seemingly infinite, intimidating expression and broken it down into a logical, step-by-step journey. This is the essence of JEE mathematics: not just finding the answer, but understanding the beautiful, logical structure that makes the answer inevitable.
The sequence an is bounded above by 7 for all n≥1. Keep practicing, keep questioning, and never stop loving the process.