Sigma Percentile
JEE Main 2002
LEVELJEE Main

Animated Solution for Mathematics - Sequence and Series: If having radical signs then by methods of mathematical induction which is true

Select Answer:

Visualized Solution

The Nested Radical Sequence

  • Given sequence:
  • The sequence has radical signs.
  • We need to find an upper bound using Mathematical Induction.

Recursive Definition

  • Let's write the first few terms.
  • General recursive relation:

Graphical Perspective

  • Let represent our recursive function.
  • The line helps us map to .
  • The sequence terms can be visualized as a cobweb plot.

Base Case ()

  • We will test the inequality .
  • For :

Evaluating the Base Case

  • We know that .
  • Therefore, .
  • The base case holds true!

Inductive Hypothesis

  • Assume the statement is true for some integer .
  • Assumption:

Inductive Step Goal

  • We must prove the statement is true for .
  • To Prove:

Applying the Recursive Formula

  • Recall the recursive relation:

Building the Inequality

  • From our assumption:

Adding 7 to Both Sides

  • Add to both sides of the inequality:

Taking the Square Root

  • Take the positive square root on both sides:

Finalizing the Inductive Step

  • We know , which is strictly less than .
  • Therefore,
  • This means .

Conclusion

  • By the Principle of Mathematical Induction, for all .
  • The sequence is bounded above by .
  • Correct Option:

The Sigma Insight: Sum of Special Series

Solution Diagram

Analyzing the Recursive Heart

Let us define our sequence with radical signs. If you look closely, you will see a beautiful self-similarity.
The term is , which is just . Similarly, is .
This reveals the recursive soul of our sequence:
This simple relation is the key to everything. We are not dealing with a static number; we are dealing with a dynamic process where each term feeds into the next.

The Domino Effect

Mathematical Induction is like a row of dominoes. If we can prove that the first domino falls (the base case) and that one falling domino will always knock over the next (the inductive step), then the entire sequence must fall into place.
For our base case, , we have . Since and , we know that .
Thus, . The first domino has fallen!

The Inductive Leap

Now, we assume the statement is true for some integer , meaning we assume . This is our inductive hypothesis.
Our mission is to prove that . We start with our assumption: .
First, add 7 to both sides:
Now, take the square root of both sides:
Since , and , we have successfully shown that .

The Grand Conclusion

By the Principle of Mathematical Induction, we have proven that for all .
We have taken a seemingly infinite, intimidating expression and broken it down into a logical, step-by-step journey. This is the essence of JEE mathematics: not just finding the answer, but understanding the beautiful, logical structure that makes the answer inevitable.
The sequence is bounded above by 7 for all . Keep practicing, keep questioning, and never stop loving the process.

Similar Questions

JEE Main 2008
LEVELBoard

Statement-1 : For every natural number . Statement-2 : For every natural number .

(A)
Statement -1 is false, Statement-2 is true
(B)
Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1
(C)
Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(D)
Statement -1 is true, Statement-2 is false
JEE Main 2004
LEVELJEE Main

Let . Then which of the following is true

(A)
Principle of mathematical induction can be used to prove the formula
(B)
(C)
(D)
is correct
JEE Advanced 1999
LEVELJEE Main

For a positive integer , let . Then

* Multiple Correct Options
(A)
(B)
(C)
(D)
JEE Main 2022 (29 June Shift 1)
LEVELJEE Main

Let be a sequence such that and for all . Then, is equal to

(A)
(B)
(C)
(D)
JEE Advanced 1988
LEVELJEE Main

Sum of the first terms of the series is equal to

(A)
(B)
(C)
(D)
JEE Main 2026 (24 January Shift 2)
LEVELJEE Main

upto infinite terms, is equal to

(A)
4/3
(B)
6/5
(C)
5/2
(D)
7/4
JEE Advanced 2019
LEVELJEE Advanced

Let and be the roots of , with . For all positive integers , define , and . Then which of the following options is/are correct?

* Multiple Correct Options
(A)
for all
(B)
(C)
(D)
for all
JEE Advanced 1983
LEVELJEE Main

Use mathematical Induction to prove : If is any odd positive integer, then is divisible by 24.

JEE Main 2021 (20 July Shift 2)
LEVELJEE Main

Let be a sequence such that and for all . Then the value of is equal to

JEE Main 2023 (24 January Shift 2)
LEVELJEE Main

If , then the value of is