Decoding the Quantum Graph
Imagine you are an explorer trying to map out the exact location of an electron around a nucleus. The graph provided in the question is your map. It plots the probability density, denoted mathematically as ∣ψ∣2, against the radial distance r from the nucleus.
Notice how the curve starts at a high value on the y-axis. This immediately tells us a profound secret: the electron has a high probability of being found very close to the nucleus. This behavior is an exclusive signature of s-orbitals (l=0). For any other orbital (like p, d, or f), the probability density at the nucleus is strictly zero.
The Secret of Radial Nodes
As we trace the curve moving away from the nucleus, the probability density drops sharply, hits absolute zero, and then rises again to form a smaller secondary peak before finally fading away into the distance.
That exact point where the curve touches the horizontal axis (∣ψ∣2=0) is called a radial node. It is a spherical region in space where the probability of finding the electron is absolutely zero.
In quantum mechanics, the number of radial nodes for any given orbital is governed by a beautifully simple formula:
Where n is the principal quantum number and l is the azimuthal quantum number.
Testing the Candidates
By simply looking at our graph, we can count exactly one radial node. Now, let's put our four candidates to the test using our formula:
For the
1s-orbital (
n=1,l=0):
1−0−1=0 nodes
For the
2p-orbital (
n=2,l=1):
2−1−1=0 nodes
For the
3s-orbital (
n=3,l=0):
3−0−1=2 nodes
For the
2s-orbital (
n=2,l=0):
2−0−1=1 node
The Final Verdict
The math aligns perfectly with our visual evidence. The 2s-orbital is the only candidate that possesses exactly one radial node. Furthermore, because it is an s-orbital, it correctly starts from a maximum probability density at the nucleus. Therefore, the graph undeniably represents the 2s-orbital.