Sigma Percentile
JEE Main 2021
LEVELJEE Main

Animated Solution for Chemistry - Atomic Structure: A certain orbital has no angular nodes and two radial nodes. The orbital is

Select Answer:

Visualized Solution

Node Formulas

Given Conditions

Identifying the Subshell

Calculating Principal Quantum Number

Final Orbital

The Sigma Insight: Quantum Mechanical Model

Solution Diagram

The Anatomy of an Orbital

To truly master atomic structure, you must understand the concept of nodes. Imagine an electron as a cloud of probability around the nucleus. A node is simply a region in space where this probability drops to exactly zero. It is a "blind spot" where the electron can never be found.
There are two distinct types of nodes that define the geometry of an orbital: angular nodes and radial nodes.
Angular nodes are flat planes or conical surfaces that slice through the nucleus. The number of angular nodes is directly given by the azimuthal quantum number, .
Radial nodes, on the other hand, are spherical shells of zero probability—like the empty spaces between the layers of an onion. The number of radial nodes is calculated using the formula , where is the principal quantum number.

Decoding the Clues

The problem provides us with two critical pieces of information. First, the orbital has zero angular nodes.
Mathematically, this means:
In the language of quantum mechanics, an value of strictly corresponds to an -orbital. Because -orbitals are perfectly spherical, they possess no planar or conical cuts. This single deduction immediately eliminates any , , or orbital options.

Solving for the Shell

The second clue states that the orbital has exactly two radial nodes. We can set up our radial node equation and substitute the value of we just found:
Substituting into the equation:

The Final Picture

We have successfully decoded both quantum numbers! The principal quantum number is , and the azimuthal quantum number is .
Combining these two pieces of information, the orbital in question is the orbital. If you were to plot the radial probability density function () for a orbital against the distance from the nucleus (), you would observe exactly three peaks separated by two distinct points where the curve touches the horizontal axis. Those two points are the physical manifestation of the two radial nodes we just calculated.

Similar Questions

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